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3 years ago

A direct result of european exploration of north america during the 1500s and early 1600s was the

Physics

1 answer:

gogolik [260]3 years ago

7 0

Answer:

introduction of new animals and crops to North America

Explanation:

Since the early 1500s, Europeans have transported old world species to their new settlements in the Western Hemisphere, as well as to other parts of the world. The manifestoes of Christopher Columbus' second and subsequent voyages, for example, mention the deliberate transportation of species considered potential crops and livestock. Global trade has grown astronomically since then, providing an opportunity for the corresponding growth of biological invasions. Consequently, biological invasions can be viewed as a predominantly post-Columbian event. Put in perspective, the movement of organisms caused by humans, accidentally or deliberately in the last 200 to 500 years, undoubtedly dwarfs in frequency and impact the movement of organisms by natural forces at any 500-year period in Earth's history.

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Find deacceleration An engineer in a locomotive sees a car stuck on the track at a railroad crossing in front of the train. When

earnstyle [38]

Answer:

The deceleration is $a = -0.7273 \ m/s^2$

Explanation:

From the question we are told that

The distance of the car from the crossing is $d = 360 \ m$

The speed is $u = 16 \ m/s$

The reaction time of the engineer is $t = 0.53 \ s$

Generally the distance covered during the reaction time is

$d_r = u * t$

=> $d_r = 16 * 0.53$

=> $d_r = 8.48 \ m$

Generally distance of the car from the crossing after the engineer reacts is

$D = d- d_r$

=> $D = 360 - 8.48$

=> $D = 352 \ m$

Generally from kinematic equation

$v^2 = u^2 + 2as$

Here v is the final velocity of the car which is 0 m/s

$0^2 = 16^2 + 2 * a * 352$

=> $a = -0.7273 \ m/s^2$

3 0

3 years ago

The star Rho1 Cancri is 57 light-years from the earth and has a mass 0.85 times that of our sun. A planet has been detected in a

s344n2d4d5 [400]

Answer:

82780.42123 m/s

14.45 days

Explanation:

m = Mass of the planet

M = Mass of the star = $0.85\times 1.989\times 10^{30}\ kg=1.69065\times 10^{30}\ kg$

r = Radius of orbit of planet = $0.11\times 149.6\times 10^{9}\ m=16.456\times 10^{9}\ m$

v = Orbital speed

The kinetic and potential energy balance is given by

$\frac{GMm}{r^2}=\frac{mv^2}{r}\\\Rightarrow v=\sqrt{\dfrac{Gm}{r}}\\\Rightarrow v=\sqrt{\dfrac{6.67\times 10^{-11}\times 1.69065\times 10^{30}}{16.456\times 10^{9}}}\\\Rightarrow v=82780.42123\ m/s$

The orbital speed of the star is 82780.42123 m/s

The orbital period is given by

$t=\frac{2\pi r}{v}\\\Rightarrow t=\dfrac{2\pi \times 16.456\times 10^{9}}{82780.42123}\\\Rightarrow t=1249040.48419\ seconds=\dfrac{1249040.48419}{24\times 60\times 60}=14.45\ days$