Explanation:
It is given that,
The speed of light in vacuum is, c = 299,792,458 m/s
The permeability constant of vacuum is, 
Let
is the permittivity of free space. The relation between
is given by :




Hence, this is the required solution.
Check bing for the answer
Explanation:
energy cannot be created or destroyed, but only changed from one form to another or transferred from one object to another.
The
structure of an individual molecule will determine which substance will dissolve.
<u>Option: A</u>
<u>Explanation:</u>
Once a solvent disintegrates, the single atoms, molecules or ions communicate with the solvent, become solved, and are able to diffuse in the solution independently. However, this is not a unidirectional method. When the molecule or ion collides with the surface of an undissolved solute particle, it may bind to the particle in a method called crystallization.
The concentration units or structure are used to define the degree to which a solvent is soluble. A solution can be categorized as hydrophilic (water-loving), implying it has an electrostatic water-looking attraction, or hydrophobic (water-fearing), implying it repels water. A hydrophilic material is polar, and mostly includes groups of O–H or N–H that can shape water bonds.
Answer:
The answer is 138.5
Explanation:
STEP 1:
The inductance per unit length of a coaxial transmission line is
L′=L<em>/ </em>I
=Ø/H
=μoI/2π In (b/a)
In this a is the radius of inner conductor
b is the radius of outer conductor
I is the coaxial transmission
μ is the magnetic permeability
Since the transmission of the charge exists in air, the value of the relative permeability is μr= I and permeability of free space is μo= 4π x 10-7 H/m . So the magnetic permeability will be
μ = μoμ r
μ =μ o(I) 4π x 10-7 H/m
L′= μoI/2π In (b/a)
= (4π x 10-7 ) (2)/2π In (10/5)
=2.77 x 10-7 H
STEP 2:
Obtain the magnetic energy stores in the magnetic field H of a volume of the coaxial transmission line containing a material with permeability μ, by using the formula given below:
Wm= 1/2 LI^2
= 1/2 (2.77x 10^-7 I^2
= 138.5 X 10^-9 I^2 J
Now we will simplify the equation
Wm= 185.5<em>I</em>^2 nJ
So, the magnetic energy stored in insulating medium is 185.5<em>I</em>^2 nJ