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Tanya [424]
3 years ago
12

Using kinetic molecular theory and collision theory, explain why the absolute temperature scale (kelvins) is more appropriate th

an celsius for explaining the effect of temperature on reaction rate
Physics
2 answers:
Nezavi [6.7K]3 years ago
5 0
According  to   kinetic   molecular  theory  temperature  is  a  measure  of  kinetic  energy.There  is  absolute  minimum  temperature  which  occurs  when  something  completely  stop  moving   whereby  temperature  cannot  become  lower   than   this  point. The   absolute  zero  which  has  been  extrapolated  to  exist  at  about  -273  celsius  while  in   kelvin  scale  is  set  such  that  absolute  zero  is 0  k  thus  kelvin   is  better   inorder  to  avoid  negative  number  when  calculating. 
Elanso [62]3 years ago
3 0
<h2><u>Answer:</u></h2>

The kinetic theory of gases states that <em>the total average energy of the movement (translation) of a molecule is directly proportional to the absolute temperature of the gas</em>. Then, as the temperature increases, the number of collisions increases, since the higher the temperature, the greater the number of collisions.

Therefore, the reaction rate will increase as the temperature increases.

In other words :

If a reaction suffers an increase in temperature or concentration, it will generate an increase in the number of effective collisions.

In this context, a change in temperature in the Kelvin scale is <u>directly related</u> to kinetic energy of the molecules, hence the 0 degrees Kelvin represents zero kinetic energy; while the Celsius scale is <u>indirectly related</u> kinetic energy, it is based on the range between freezing and boiling water temperatures in 100 equal parts, this means the zero degrees Celsius is based on the change in temperature in water and is not the absolute zero.


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A bicycle wheel has a diameter of 63.0 cm and a mass of 1.75 kg. Assume that the wheel is a hoop with all of the mass concentrat
Masteriza [31]

Answer:

F2 = 834 N

Explanation:

We are given the following for the bicycle;

Diameter; d1 = 63 cm = 0.63 m

Mass; m = 1.75 kg

Resistive force; F1 = 121 N

For the sprocket, we are given;

Diameter; d2 = 8.96 cm = 0.0896 m

Radius; r2 = 0.0896/2 = 0.0448 m

Radial acceleration; α = 4.4 rad/s²

Now moment of inertia of the wheel which is assumed to be a hoop is given by; I = m(r1)²

Where r1 = (d1)/2 = 0.63/2

r1 = 0.315 m

Thus, I = 1.75 × 0.315²

I = 0.1736 Kg.m²

The torque is given by the relation;

I•α = F1•r1 - F2•r2

Where F2 is the force that must be applied by the chain to give the wheel an acceleration of 4.40 rad/s².

Thus;

0.1736 × 4.4 = (121 × 0.315) - (0.0448F2)

>> 0.76384 = 38.115 - (0.0448F2)

>> 0.0448F2 = 38.115 - 0.76384

>> F2 = (38.115 - 0.76384)/0.0448

>> F2 = 833.73 N

Approximately; F2 = 834 N

7 0
3 years ago
Pls answer I will make brainlist
Semenov [28]
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3 0
3 years ago
An 80-kg astronaut becomes separated from his spaceship. He is 15.0 m away from it and at rest relative to it. In an effort to g
9966 [12]

The astronaut will take 300 seconds

Explanation:

We can solve this problem by using the law of conservation of momentum.

In fact, the total momentum of the astronaut+object system must be conserved.

Initially, they are both at rest, so their total momentum is zero:

p=0

After the astronaut throws the object, their total momentum is:

p=MV+mv

where:

M = 80 kg is the mass of the astronaut

V is the final velocity of the astronaut

m = 500 g = 0.5 kg is the mass of the object

v = 8.0 m/s is the velocity of the object

Since momentum is conserved, we can write

0=MV+mv

And solving for V,

V=-\frac{mv}{M}=-\frac{(0.5)(8.0)}{80}=-0.05 m/s

Which means that he starts moving at 0.05 m/s in the direction opposite to the object.

Now the astronaut needs to cover a distance of

d = 15.0 m

And his speed is

v = 0.05 m/s

Therefore, the time taken is

t=\frac{d}{v}=\frac{15.0}{0.05}=300 s

Learn more about momentum here:

brainly.com/question/7973509

brainly.com/question/6573742

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3 0
3 years ago
A temperature of 200°F is equivalent to approximately
aev [14]
<span>93.3°C
A temperature in Fahrenheit (°F) can be converted to Celsius (°C), using the formula
[°C] = ([°F] − 32) ×  5⁄9. Here we have to convert a temperature of 200°F in to Celsius. Thus Subtract 32 from Fahrenheit and multiply by 5 then divide by 9 . That is (200°F - 32) × 5/9=168 × 5/9
                                          =840/9
                                          =93.333333333°C
                                          = 93.3°C</span>
7 0
3 years ago
Read 2 more answers
Big Bob is on his Harley and moving at 14.0m/s. He then accelerates to a velocity of 25m/s over a distance of 0.250 km. What is
Xelga [282]

As we know that it has all given data given as

v_i = 14 m/s

v_f = 25 m/s

distance moved = 0.250 km = 250 m

now we can use kinematics to find acceleration

v_f^2 - v_i^2 = 2 a d

25^2 - 14^2 = 2 * a * 250

a = 0.86 m/s^2

so it will accelerate at rate of 0.86 m/s^2


8 0
3 years ago
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