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Tanya [424]
3 years ago
12

Using kinetic molecular theory and collision theory, explain why the absolute temperature scale (kelvins) is more appropriate th

an celsius for explaining the effect of temperature on reaction rate
Physics
2 answers:
Nezavi [6.7K]3 years ago
5 0
According  to   kinetic   molecular  theory  temperature  is  a  measure  of  kinetic  energy.There  is  absolute  minimum  temperature  which  occurs  when  something  completely  stop  moving   whereby  temperature  cannot  become  lower   than   this  point. The   absolute  zero  which  has  been  extrapolated  to  exist  at  about  -273  celsius  while  in   kelvin  scale  is  set  such  that  absolute  zero  is 0  k  thus  kelvin   is  better   inorder  to  avoid  negative  number  when  calculating. 
Elanso [62]3 years ago
3 0
<h2><u>Answer:</u></h2>

The kinetic theory of gases states that <em>the total average energy of the movement (translation) of a molecule is directly proportional to the absolute temperature of the gas</em>. Then, as the temperature increases, the number of collisions increases, since the higher the temperature, the greater the number of collisions.

Therefore, the reaction rate will increase as the temperature increases.

In other words :

If a reaction suffers an increase in temperature or concentration, it will generate an increase in the number of effective collisions.

In this context, a change in temperature in the Kelvin scale is <u>directly related</u> to kinetic energy of the molecules, hence the 0 degrees Kelvin represents zero kinetic energy; while the Celsius scale is <u>indirectly related</u> kinetic energy, it is based on the range between freezing and boiling water temperatures in 100 equal parts, this means the zero degrees Celsius is based on the change in temperature in water and is not the absolute zero.


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Complete Question

A gas gun uses high pressure gas tp accelerate projectile through the gun barrel.

If the acceleration of the projective is : a = c/s m/s​2

Where c is a constant that depends on the initial gas pressure behind the projectile. The initial position of the projectile is s= 1.5m and the projectile is initially at rest. The projectile accelerates until it reaches the end of the barrel at s=3m. What is the value of the constant c such that the projectile leaves the barrel with velocity of 200m/s?

Answer:

The value of the constant is  c = 28853.78 \ m^2 /s^2

Explanation:

From the question we are told that

         The acceleration is  a =  \frac{c}{s}\   m/s^2

         The  initial position of the projectile is s= 1.5m

         The final position of the projectile is s_f =  3 \ m

          The velocity is  v = 200 \ m/s

     Generally  time  =  \frac{ds}{dv}

   and  acceleration is a =  \frac{v}{time }

so

            a = v  \frac{dv}{ds}

 =>        vdv  =  a ds

             vdv  = \frac{c}{s}  ds

integrating both sides

           \int\limits^a_b  vdv  = \int\limits^c_d \frac{c}{s}  ds

Now for the limit

          a =  200 m/s

             b = 0 m/s  

         c = s= 3 m

          d =s_f= 1.5 m

So we have  

           \int\limits^{200}_{0}  vdv  = \int\limits^{3}_{1.5} \frac{c}{s}  ds

              [\frac{v^2}{2} ] \left | 200} \atop {0}} \right.  = c [ln s]\left | 3} \atop {1.5}} \right.

            \frac{200^2}{2}  =  c ln[\frac{3}{1.5} ]

=>           c = \frac{20000}{0.69315}

              c = 28853.78 \ m^2 /s^2

     

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