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2 years ago

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A brick is released with no initial speed from the roof of a building and strikes the ground in 2.50 s, encountering no apprecia

ble air drag. How tall, in meters, is the building?

1 answer:

Elenna [48]2 years ago

6 0

Answer:A brick is released with no initial speed from the roof of a building and strikes the ground in 2.50 s, encountering no ..

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Given that the effective mass ratio of the electron is 0.11 and the effective mass ratio of the hole is 0.35, please calculate t

fomenos

Complete question:

CdTe has a band-gap energy εg of 1.6 eV and a dielectric constant εr of 10.9.

Given that the effective mass ratio of the electron is 0.11 and the effective mass ratio of the hole is 0.35, please calculate the ground-state energy (ie: n=1) of the donor and acceptor bands along with their orbital radii.

Answer:

The ground-state energy for donor is 2.6 meV

The ground-state energy for acceptor is 40.1 meV

Explanation:

Given;

effective hole mass, Mh = 0.35

effective electron mass, Me = 0.11

mass of electron, M₀ = 9.11 x 10⁻³¹

dielectric constant, εr = 10.9

To determine the donor and acceptor energies, we apply the equation below;

E = 1 Rydberg x m*/(m₀εr²)

E = 13.606 eV x m*/(m₀εr²)

The ground-state energy for donor = 13.606 eV x M*/(M₀εr²)

= 13.606 eV x Me/(εr²)

= 13.606 eV x 0.11/((10.9)²)

= 2.6 meV

The ground-state energy for acceptor = 13.606 eV x M*/(M₀εr²)

= 13.606 eV x Mh/(εr²)

= 13.606 eV x 0.35/((10.9)²)

= 40.1 meV

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3 years ago

What are possible units for impulse? Check all that apply.

Gemiola [76]

Answer:

kg.m/s

Explanation:

it is a division of a mass and a speed

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If you rub a balloon on a piece of fabric or carpeting and then hold it against your head, your hair can stand on end. Use what

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a jet plane traveling 1890 km/h pulls out of a dive by moving in an arc of radius 5.20km. what is planes acceleration in g's

Andrew [12]

Answer:

$53 m/s^2$

Explanation:

Unit conversions:

1890 km/h = 1890 km/h * 1000m/km * 1/3600 h/s = 525 m/s

5.2 km = 5200 m

Assume that the jets is traveling in perfect circular motion, we can calculate the centripetal acceleration of the motion:

$a = \frac{v^2}{r}$

where v = 525m/s is the velocity of the jet and r = 5200 is the radius of the arc

$a = \frac{525^2}{5200} = 53m/s^2$

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