Simplify the expression.20 • 5

Select all of the following ordered pairs that are in the solution set of the inequality shown

Goshia [24]

The answers would be (0,10) , (20,0) , and (100,100)

5 0

3 years ago

Read 2 more answers

Describe an animal adaptation and explain how it helps survival.

marin [14]

Answer and Step-by-step explanation:

Animal adaption for Birds.

Birds who live on a tropical island with large, hard shell nuts.

The birds have small beaks, but over time, their beaks become bigger, stronger, and sharper, so that it can break into the hard shell nuts, allowing them to eat the nuts.

<em><u>#teamtrees #WAP (Water And Plant)</u></em>

3 0

3 years ago

Perimeter of a quarter circle is 17.85 what is the quarter circles radius

givi [52]

The radius of the given circle is 2.84 units

Step-by-step explanation:

Step 1 :

Given

The perimeter of a quarter table is 17.85

We need to find the circle's radius.

Step 2 :

The circle's perimeter is given by the formula, 2 $\pi$ r where r represents the circle's radius

So from this we have ,

2 $\pi$ r = 17.85

We can determine the radius by dividing the perimeter value by 2 $\pi$

= > r = 17.85 divided by 2 $\pi$ r

= 2.84 [ taking $\pi$ = $\frac{22}{7}$ ]

Step 3 :

Answer :

The radius of the given circle is 2.84 units

4 0

4 years ago

A dataset lists full IQ scores for a random sample of subjects with low lead levels in their blood (sample 1) and another random

Alenkasestr [34]

Answer:

a. Null hypothesis: $\mu_1 \leq \mu_2$

Alternative hypothesis: $\mu_1 >\mu_2$

b. $t=\frac{(92.88 -86.90)-(0)}{\sqrt{\frac{15.34^2}{78}}+\frac{8.99^2}{21}}=2.282$

c. $p_v =P(t_{97}>2.287) =0.0122$

So with the p value obtained and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (Low Blood Lead level) is significantly higher than the mean for the group 2 (High Blood Lead level).

Step-by-step explanation:

a. State and label the null and alternative hypotheses.

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 \leq \mu_2$

Alternative hypothesis: $\mu_1 >\mu_2$

Or equivalently:

Null hypothesis: $\mu_1 - \mu_2 \leq 0$

Alternative hypothesis: $\mu_1 -\mu_2>0$

Our notation on this case :

$n_1 =78$ represent the sample size for group 1

$n_2 =21$ represent the sample size for group 2

$\bar X_1 =92.88$ represent the sample mean for the group 1

$\bar X_2 =86.90$ represent the sample mean for the group 2

$s_1=15.34$ represent the sample standard deviation for group 1

$s_2=8.99$ represent the sample standard deviation for group 2

b. State the value of the test statistic.

And the statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sqrt{\frac{s^2_1}{n_1}}+\frac{s^2_2}{n_2}}$

Where t follows a t distribution with $n_1+n_2 -2$ degrees of freedom. If we replace the values given we have:

$t=\frac{(92.88 -86.90)-(0)}{\sqrt{\frac{15.34^2}{78}}+\frac{8.99^2}{21}}=2.282$

Now we can calculate the degrees of freedom given by:

$df=78+21-2=97$

c. Find either the critical value(s) and draw a picture of the critical region(s) or find the P-value for this test. Indicate which method you are using: ( CIRCLE ONE: Critical value / P-value )

Method used: P value

And now we can calculate the p value using the altenative hypothesis, since it's a right tail test the p value is given by:

$p_v =P(t_{97}>2.287) =0.0122$

So with the p value obtained and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (Low Blood Lead level) is significantly higher than the mean for the group 2 (High Blood Lead level).

6 0

4 years ago

You deposit $3000 into a bank account that pays 1.25% annual interest, compounded semi-annually. What is the final balance after

mojhsa [17]

Answer:

$3,153.32

Step-by-step explanation:

Given that

The deposited amount is $3,000

The annual interest rate is 1.25%

So, the semi-annual interest rate is 1.25% ÷2 = 0.625%

And, the time period = 4 × 2 = 8

We need to find out the final balance

So,

As we know that

Future value = Present value × (1 + rate of interest)^number of years

= $3,000 × (1 + 0.625%)^8

= $3,153.32

8 0

3 years ago

Simplify the expression.20 • 5–2