Answer:
of carbon dioxide gas.
Explanation:
Average distance covered by Americans in a day= 
1 day = 24 × 60 min = 1,440 min
Average distance covered by Americans in a minute= 
Average mileage of the car = 20 miles/gal = 32.18 km/gal
1 mile = 1.609 km
20 miles = 20 × 1.609 km = 32.18 km
Volume of gasoline used in minute = 
(1 L = 1000 mL)
Mass of 86,320.00 gallons of gasoline = m
Density of the gasoline = d = 
1 kilogram of gasoline gives 3 kg of carbon dioxde gas .
Then 303,882.84649 kg of gasoline will give :
of carbon dioxide gas.
Answer:
in the periodic table we can see that the ions of Cl is greater than the ions in Na
We can use the ideal gas law equation to find the pressure
PV = nRTwhere
P - pressure
V - volume - 2.6 x 10⁻³ m³
n - number of moles - 0.44 mol
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature - 25 °C + 273 = 298 K
substituting the values into the equation,
P x 2.6 x 10⁻³ m³ = 0.44 mol x 8.314 Jmol⁻¹K⁻¹ x 298 K
P = 419 281.41 Pa
101 325 Pa is equivalent to 1 atm
Therefore 419 281.41 Pa - 1/ 101 325 x 419 281.41 = 4.13 atm
Pressure is 4.13 atm
Answer:
10425 J are required
Explanation:
assuming that the water is entirely at liquid state at the beginning , the amount required is
Q= m*c*(T final - T initial)
where
m= mass of water = 25 g
T final = final temperature of water = 100°C
T initial= initial temperature of water = 0°C
c= specific heat capacities of water = 1 cal /g°C= 4.186 J/g°C ( we assume that is constant during the entire temperature range)
Q= heat required
therefore
Q= m*c*(T final - T initial)= 25 g * 4.186 J/g°C * (100°C- 0°C) = 10425 J
thus 10425 J are required
Answer:
Its B I just took the test and got a 100%
Explanation:
