54 mL Ba(OH)2x(0.101 mol Ba(OH)2/1000 mL) x (2 mol OH-/ 1 mol Ba(OH)2 ) = 0.0109 mol OH-
0.0109 mol OH-x (1mol HCl/ 1 mol OH- ) = 0.0109 mol HCl
0.109 mol HCl/(0.130 mol/L HCl) = 0.0839 L HCl
0.0839 L HCl * 1000mL = 83.9 mL of 0.130 M HCl
The correct answer as to which observation most likely indicates that only a chemical change has taken place would that the change cannot be reversed.
When it comes to changes in a system, it can either be:
- physical change
- chemical change
When a substance undergoes a physical change, the original version of the substance can be recovered. In other words, physical changes can be reversible.
When a substance undergoes a chemical change, the original version cannot be recovered because an entirely new product would have been formed. In other words, chemical changes are irreversible.
Thus, once a change becomes irreversible, such a change is said to be a chemical change.
More on chemical change can be found here: brainly.com/question/1161517
The phrase that describes a characteristic of an Arrhenius base is that Arrhenius base add hydroxide ions to the solution ( answer C)
<u><em>Explanation</em></u>
Arrhenius base is a substance that increases the concentration of OH- in aqueous solution.
The Common Arrhenius base are group 1 and 2 hydroxide such as LiOH, NaOH , Ba(OH)2 among others.
for example NaOH dissociate as follows , NaOH → Na+(aq) + OH- (aq)
Answer:
<em>The type of vegetation a surface does affect the </em><em>water coming from above to sink in or runoff. </em>
Explanation:
This is how the vegetation affects the runoff:-
The leaves and stems present in the vegetation do not let the water fall directly on the soil and makes the process rather slow which makes the water to get to the ground slowly and sink in properly inside the soil rather than running off.
If the vegetation present is dense with there was being hairy then also the water would not run out and will get absorbed by the roots letting the soil intact
(missing part of your question):
when we have K = 1 x 10^-2 and [A] = 2 M & [B] = 3M & m= 2 & i = 1
So when the rate = K[A]^m [B]^i
and when we have m + i = 3 so the order of this reaction is 3 So the unit of K is L^2.mol^-2S^-1
So by substitution:
∴ the rate = (1x 10 ^-2 L^-2.mol^-2S^-1)*(2 mol.L^-1)^2*(3mol.L^-1)
= 0.12 mol.L^-1.S^-1
