Answer:
25.907°C
Explanation:
In Exercise 102, heat capacity of bomb calorimeter is 6.660 kJ/°C 
The heat of combustion of benzoic acid is equivalent to the total heat energy released to the bomb calorimeter and water in the calorimeter.
Thus:

 = heat of combustion of benzoic acid
 = heat of combustion of benzoic acid
 = heat energy released to water
 = heat energy released to water
 = heat energy released to the calorimeter
 = heat energy released to the calorimeter
Therefore,
![-m_{combust}*H_{combust} = [m_{water}*c_{water} + C_{calori}]*(T_{f} - T_{i})](https://tex.z-dn.net/?f=-m_%7Bcombust%7D%2AH_%7Bcombust%7D%20%3D%20%5Bm_%7Bwater%7D%2Ac_%7Bwater%7D%20%2B%20C_%7Bcalori%7D%5D%2A%28T_%7Bf%7D%20-%20T_%7Bi%7D%29)
1.056*26.42 = [0.987*4.18 + 6.66]( - 23.32)
 - 23.32)
27.8995 = [4.12566+6.660]( - 23.32)
 - 23.32)
( - 23.32) = 27.8995/10.7857 = 2.587
 - 23.32) = 27.8995/10.7857 = 2.587
 = 23.32 + 2.587 = 25.907°C
 = 23.32 + 2.587 = 25.907°C
 
        
             
        
        
        
Explanation:
Immunoglobulin M is the first antibody produced on initial exposure to an antigen. It is also known as IgM.
It occurs as a primary response to the antigens against a particular baterium or virus. It is pentavalent in nature and has ten binding sites for antigens.
 Therefore, it is concluded that when the body identifies a bacterium or a virus, it releases the antibody IgM.
 
        
                    
             
        
        
        
Answer:
Just Send Answers to make points
Explanation:
 
        
             
        
        
        
3 to balance the calciums on both sides of the equation, but only if that balances the Cl on both sides of the equation to because you now have 6 Cl and 3Ca 
        
                    
             
        
        
        
Answer:
Final volumeof the gas = 2.84 L
Explanation:
The formular to be used here is the general gas equation. the formular is being used because it gives the relationship between the three gas parameters (volume, temperature and pressure) mentioned.
The general gas equation is given as;

where;
P1 = initial pressure
V1 = initial volume
T1 = initial temperature
P2 = Final pressure
V2 = Final volume
T2 = Final temperature
From the question,
P1 = 1.00 atm
P2 = 0.85atm
T1 = 25C + 273 = 298K (Converting to kelvin)
T2 = 15C + 273 = 288K (Converting to kelvin)
V1 = 2.5L
V2 = ?
from the equation, making V2 subject of formula we have;

V2 = (1*2.5*288)/(298*0.85) = 2.84 L.