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Studentka2010 [4]
3 years ago
12

3 A roller coaster car travels up a hill until it reaches the top, slowly goes over, and speeds down the hill and through the nu

st of the roller coaster. At the end, the brakus quickly stop the car and the riders appear to continue moving forward. Which of Newton's laws of motion best applies to the riders of the roller coaster?​
Chemistry
1 answer:
STALIN [3.7K]3 years ago
8 0

Answer:

3rd law

Explanation:

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Please help me solve? Chemistry
oee [108]
1000mL
1mL
100cm
1m
2,290,000 L

8 0
3 years ago
A cell has the reaction Co2+ (aq) + Cd(s) -------> Cd2+ (aq) + Co(s) E0cell = +0.120 V What is Ecell when [Co2+] = 0.00100 M
musickatia [10]

Answer:

USe this Nernst equation and find your required answer

Explanation:

E = E0 -  [0.0592 /n ] log [Cd+2]/[Co2+]

Wher Eo is  +0.120 V

[Cd+2] =0.1

[Co2+] = 0.001

n is number of electons transfered int he process and in your case it is = 2

E= 0.120- 0.0296 * log 100

  = ........  V

5 0
3 years ago
In what way would one dozen elephants and one dozen doughnuts be similar?
Gnoma [55]

Answer:

both are a number group of 12

Explanation:

dozen=12

4 0
4 years ago
What measurements are used to calculate the density of a given object?
professor190 [17]

Answer:

Density = \frac{Mass}{Volume}

Explanation:

Density equals mass divided by volume.

Density often has units of grams per cubic centimeter (g/cm3). Remember, grams is a mass and cubic centimeters is a volume (the same volume as 1 milliliter).

8 0
3 years ago
Read 2 more answers
THIS IS DUE TODAY!!!!!!!!!!!!!!!!!!!!!!!!!! PLEASE HELP ME ASAPPPPPPPP CHEMISTRY!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
allochka39001 [22]

Answer:

\large \boxed{\text{0.1767 mol/L}}$

Explanation:

(a) Balanced equation

3NaOH + H₃PO₄ ⟶ Na₃PO₄ + 3H₂O  

(b) Moles of NaOH

\text{Moles of  NaOH} = \text{34.52 mL NaOH} \times \dfrac{\text{0.3840 mmol NaOH}}{\text{1 mL NaOH}} = \text{13.26 mmol NaOH}

(c) Moles of H₃PO₄

The molar ratio is 1 mol H₃PO₄:3 mol NaOH.

\text{Moles of H$_{3}$PO}_{4} = \text{13.26 mmol NaOH} \times\dfrac{\text{ 1 mmol H$_{3}$PO}_{4}}{\text{3 mmol NaOH}}\\\\= \text{4.419 mmol H$_{3}$PO}_{4}

(d) Molar concentration of H₃PO₄

c = \dfrac{\text{moles of solute}}{\text{litres of solution}}\\\\c = \dfrac{n}{V} = \dfrac{\text{4.419 mmol}}{\text{25.00 mL}} = \text{0.1767 mol $\cdot$ L$^{-1}$}\\\\\text{The molar concentration of the NaOH is $\large \boxed{\textbf{0.1767 mol/L}}$}

7 0
3 years ago
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