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Studentka2010 [4]
3 years ago
12

3 A roller coaster car travels up a hill until it reaches the top, slowly goes over, and speeds down the hill and through the nu

st of the roller coaster. At the end, the brakus quickly stop the car and the riders appear to continue moving forward. Which of Newton's laws of motion best applies to the riders of the roller coaster?​
Chemistry
1 answer:
STALIN [3.7K]3 years ago
8 0

Answer:

3rd law

Explanation:

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BROO DEE YOU ALREADY KNOW WHAT IS STOP DA CAP, o.81
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Calculate the entropy change for the surroundings of the reaction below at 350K: N2(g) + 3H2(g) -> 2NH3(g) Entropy data: NH3
krek1111 [17]

Answer : The entropy change for the surroundings of the reaction is, -198.3 J/K

Explanation :

We have to calculate the entropy change of reaction (\Delta S^o).

\Delta S^o=S_{product}-S_{reactant}

\Delta S^o=[n_{NH_3}\times \Delta S^0_{(NH_3)}]-[n_{N_2}\times \Delta S^0_{(N_2)}+n_{H_2}\times \Delta S^0_{(H_2)}]

where,

\Delta S^o = entropy of reaction = ?

n = number of moles

\Delta S^0{(NH_3)} = standard entropy of NH_3

\Delta S^0{(H_2)} = standard entropy of H_2

\Delta S^0{(N_2)} = standard entropy of N_2

Now put all the given values in this expression, we get:

\Delta S^o=[2mole\times (192.5J/K.mole)]-[1mole\times (191.5J/K.mole)+3mole\times (130.6J/K.mole)]

\Delta S^o=-198.3J/K

Therefore, the entropy change for the surroundings of the reaction is, -198.3 J/K

4 0
3 years ago
Classify the same processes as exothermic or endothermic.
Inessa [10]

Answer:

1.endothermic

2.exothermic

3.exothermic

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2) Not quite sure about this one, sorry :(

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how much heat will be absorbed by 25g of chloroform when its temperature started at 67.0C and after it was 112.0C
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Hello friend ☺

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mass of water

C = waters specific heat capacity

ΔT = change in temperature

and so ΔH = 25 × 4.18 × ( 112-67 ) J = 4702.5 J

Thanks ❤

8 0
3 years ago
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