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Which of the following is a correct set of quantum numbers for an electron in a 5f orbital and please explain why

alexandr1967 [171]

Answer:

Option A) n = 5, ℓ= 3, mℓ= +1 is a correct set of quantum numbers for an electron in a 5f orbital.

Explanation:

1) n is the main or principal quantum number. It is an integer number from 1. So, it may be 1, 2, 3, 4, 5, ...

2) In 5f, the principal quantum number is n = 5.

So, the possible correct choices are A) n = 5, ℓ = 3, mℓ = +1 or D) n = 5, ℓ = 4, mℓ = 3.

3) ℓ is the second or the orbital angular momentum quantum number.

ℓ can be an integer number from 0 to n - 1.

So, when n = 5, ℓ can be 0, 1, 2, 3 or 4, only one of those.

This quantum number is also the subshell or kind of orbital.

This summarizes the relation between the number and the letter that identifies the kind of orbital:

ℓ kind of orbital

0 s

1 p

2 d

3 f

So, for an electron in 5f orbital, the first two quantum numbers are n = 5, ℓ = 3.

With that, you already know that the correct choice can only be A) n = 5, ℓ = 3, mℓ = +1.

4) mℓ is the third or the magnetic quantum number. This quantum number can take the values from - ℓ to + ℓ. So, for ℓ = 3 (or f) , it can be -3, -2, -1, 0, +1, +2, or +3.

Hence, A) n = 5, ℓ= 3, mℓ= +1 is a correct set of quantum numbers for an electron in a 5f orbital.

7 0

3 years ago

Which statement describes why radiocarbon dating has an upward limit of 50 000 years

tekilochka [14]

Because The half-life of carbon-14 is around 5,700 years. So, by measuring the half-live of the sample, we could predict how old the sample actually is.
After 50,000 years there is probably less than 1% of the original C-14 left which make it much more accurate to measure, so, the upward limit is put on 50,000 years.

7 0

3 years ago

If 1.00 g of a hydrocarbon is combusted and found to produce 3.14 g of co2, what is the empirical formula of the hydrocarbon?

photoshop1234 [79]

The combustion reaction is as expressed,

CxHy + O2 --> CO2 + H2O

The mass fraction of carbon in CO2 is 3/11. Hence,
mass of C in CO2 = (3.14 g)(3/11) = 0.86 g C.

Given that we have 1 g of the hydrocarbon, the mass of H is equal to 0.14 g.

moles of C = 0.86 g C / 12 g = 0.0713
moles of H = 0.14 g H / 1 g = 0.14

The empirical formula for the hydrocarbon is therefore, CH₂.

7 0

3 years ago

What is the molar concentration (in moles/L) of a solution made with 3.744 g of Mg(NO3)2 dissolved in enough water to make 50.0

Annette [7]

Answer:

The molar concentration of a solution made with 3.744 g of Mg(NO₃)₂ dissolved in enough water to make 50.0 mL of solution is $0.5 \frac{moles}{L}$

Explanation:

Molarity or Molar Concentration is the number of moles of solute that are dissolved in a certain volume.

The molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution:

$molarity=\frac{number of moles}{volume}$

In this case:

Mg: 24.3 g/mole
N: 14 g/mole
O: 16 g/mole

So, the molar mass of Mg(NO₃)₂ is:

Mg(NO₃)₂= 24.3 g/mole + 2*(14 g/mole + 3*16 g/mole)= 148.3 g/mole

So, if you have 3.744 g of Mg(NO₃)₂, you can apply the following rule of three: if 148.3 grams of Mg(NO₃)₂ are present in 1 mole, 3.744 grams in how many moles are present?

$moles=\frac{3.744 grams*1mole}{148.3 grams}$

moles= 0.025

Then you have:

number of moles=0.025
volume= 50 mL= 0.05 L (being 1,000 mL= 1 L)

Replacing in the definition of molarity:

$molarity=\frac{0.025 moles}{0.05 L}$

you get:

$molarity=0.5 \frac{moles}{L}$

The molar concentration of a solution made with 3.744 g of Mg(NO₃)₂ dissolved in enough water to make 50.0 mL of solution is $0.5 \frac{moles}{L}$

6 0

3 years ago

Why is the cell membrane essential for cell homeostasis? A. To create food for the body B. To make energy for other tissues C. P

jek_recluse [69]

Answer: it C

Explanation: Because is the only that makes sense and the only one that seems right

3 0

4 years ago