Answer: Alkaloids
A class of substances known as alkaloids are used for their medicinal properties.
Explanation:
Alkaloids are small but complex organic substances with at least one nitrogen atom in its ring structure. Hence, they have strong basic properties, and are produced in naturally by some plants.
Examples of alkaloids and their medicinal properties are as follows:
- caffeine, used in certain drug and drinks to stimulate the nervous system
- morphine, used to reduce pain and induce sleep in humans.
- cocaine, nicotine etc
We are going to use Avogadro's constant to calculate how many molecules of
carbons dioxide exist in lungs:
when 1 mole of CO2 has 6.02 x 10^23 molecules, so how many molecules in
CO2 when the number of moles is 5 x 10^-2
number of molecules = moles of CO2 * Avogadro's number
= 5 x 10^-2 * 6.02 x 10^23
= 3 x 10^22 molecules
∴ There are 3 x 10^22 molecules in CO2 exist in lungs
Moles of X are 0.925 moles.
A mole is a totally vital unit of dimension that chemists use.The mole, symbol mol, is the unit of amount of substance inside the worldwide device of gadgets. the amount quantity of the substance is a measure of how many simple entities of a given substance are in an item or sample. The mole is described as containing exactly 6.02214076×10²³ primary entities
mass of X2O3 = 4 g
so moles = mass/molar mass
molar mass of X2O3 = 2*X + 48 -
Given, that the mass of X = 2.8g
mass of O = 4 - 2.8 = 1.2g
A mole of O = 1.2g/16 = 0.075 mole
∴ mole of X = 1 - 0.075 = 0.925 moles.
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Answer:
Molarity = 1.23 M
Explanation:
Given data:
Molarity of NaCl = ?
Mass of NaCl = 89.94 g
Volume of solution = 1249 mL ( 1249/1000 = 1.249 L)
Solution:
First of all we will calculate the number of moles of NaCl.
Number of moles = mass/molar mass
Number of moles = 89.84 g/ 58.5 g/mol
Number of moles = 1.54 mol
Molarity:
Molarity = Number of moles of solute / volume of solution in L
Molarity = 1.54 mol / 1.249 L
Molarity = 1.23 M
