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Readme [11.4K]
3 years ago
7

"how many molecules of carbon dioxide exit your lungs when you exhale 5.00 × 10−2 mol of carbon dioxide, co2?"

Chemistry
2 answers:
IrinaVladis [17]3 years ago
5 0
We are going to use Avogadro's constant to calculate how many molecules of

carbons dioxide exist in lungs:

when 1 mole of CO2 has 6.02 x 10^23 molecules, so how many molecules in

CO2 when the number of moles is 5 x 10^-2

number of molecules = moles of CO2 * Avogadro's number

                                     = 5 x 10^-2  * 6.02 x 10^23

                                     = 3 x 10^22 molecules 

∴ There are 3 x 10^22 molecules in CO2 exist in lungs 
SpyIntel [72]3 years ago
3 0
The number of CO2  molecules  that   exit  is calculated   as   follows

by use  of Avogadro   law  constant

1   mole  = 6.02 x10^23  molecules
5.00 x10^-2 mol   =?   molecules

{( 6.02  x10^23)x (5.00  x10^-2) / 1}  = 3.01 x10^22  molecules

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Answer:

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Explanation:

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mass of water = d.V = (157.0 mL)(1.0 g/cm³) = 157.0 g.

∴ mass of the solution = mass of MgCl₂ + mass of water = 20.1 g + 157.0 g = 177.1 g.

  • Now, we can get the volume of the solution:

V of the solution = (mass of the solution)/(density of the solution) = (177.1 g)/(1.089 g/cm³) = 162.62 mL = 0.163 L.

Molarity is the no. of moles of solute dissolved in a 1.0 L of the solution.

M = (no. of moles of MgCl₂) / (Volume of the solution (L)).

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