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____ [38]
4 years ago
12

A typical laboratory centrifuge rotates at 4100 rpm . test tubes have to be placed into a centrifuge very carefully because of t

he very large accelerations. part a what is the acceleration at the end of a test tube that is 10 cm from the axis of rotation? express your answer with the appropriate units.
Physics
1 answer:
alekssr [168]4 years ago
3 0

The test tube will be subject to centripetal acceleration. This acceleration is given by the following formula

(accel.) = (tangential velocity)^2 / (radius)

a = \frac{v^2}{r}

The velocity of the probe at a distance of 10 cm from the center of the centrifuge, can be calculated using the circumference of the circle:

v = 2\pi r\cdot \frac{rpm}{60} = \omega r

where omega denotes the angular velocity (radians per second). So, combining both:

v = \omega^2 r = (2\pi\cdot\frac{rpm}{60s})^2\cdot r = (2\pi\cdot\frac{4100}{60s})^2\cdot 0.1m = 18434.2 \frac{m}{s^2}

The test tube is subjected to an acceleration of 18434 m/s^2!

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4 years ago
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san4es73 [151]

Answer:

189 m/s

Explanation:

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mv²/r = mg

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So, v = √gr

v = √(9.8 m/s² × 3.63 × 10³ m)

v = √(35.574 × 10³ m²/s²)

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3 years ago
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neonofarm [45]

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Fisrtly we calculate the volume of the wire, this is given by:

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Vwire=π*1.25*10^-3*0.26=1.27*10^-6 m^3

then the number of the total electrons in tthe wire volume is given by;

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the time consuming to extract all the electrons from the wire is given by:

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4 0
3 years ago
Can you guys make a three line poem with the word time
Elina [12.6K]
Time should not be messed with
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NemiM [27]

Answer:

I think the 1st statement is right.

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3 years ago
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