What are the three common fossil fuels?

Calculate the approximate enthalpy of the reaction in joules. Estimate that 1.0 mL of vinegar has the same thermal mass as 1.0 m

Nesterboy [21]

Explanation:

The given data is as follows.

Density of vinegar = 1.0 g/ml

Specific heat capacity = 4.25 $J/g ^{o}C$

$T_{1}$ = $17 ^{o}C$ , and $T_{2}$ = $14 ^{o}C$

Relation between enthalpy and specific heat is as follows.

$\Delta H = mC \Delta T$

Hence, putting the values into the above formula as follows.

$\Delta H = mC \Delta T$

= $25 \times 1.0 \times 4.25 J/g ^{o}C \times -3^{o}C$ (as density = $\frac{mass}{volume}$ )

= - 315 J

Thus, we can conclude that the enthalpy of reaction is -315 J.

As the value is negative so, it means that heat is releasing. Hence, the reaction is exothermic in nature.

5 0

2 years ago

How much carbon dioxide will be formed if 12.5 grams of oxygen reacts with 7.2 grams of propane (C3H8 )? Balanced equation: C3H8

solong [7]

Answer:

10.3125 grams of carbon dioxide will be formed.

Explanation:

The balanced reaction is:

C₃H₈ + 5 O₂→ 3 CO₂ + 4 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles participate in the reaction:

C₃H₈: 1 mole
O₂: 5 moles
CO₂: 3 moles
H₂O: 4 moles

Being the molar mass of the compounds:

C₃H₈: 44 g/mole
O₂: 32 g/mole
CO₂: 44 g/mole
H₂O: 18 g/mole

then by stoichiometry of the reaction, the following amounts of mass participate in the reaction:

C₃H₈: 1 mole* 44 g/mole = 44 g
O₂: 5 moles* 32 g/mole= 160 g
CO₂: 3 moles* 44 g/mole= 132 g
H₂O: 4 moles* 18 g/mole= 72 g

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, it is possible to use a simple rule of three as follows: If by reaction stoichiometry 44 grams of propane react with 160 grams of oxygen, 7.2 grams of propane react with how much mass of oxygen?

$mass of oxygen=\frac{7.2 grams of propane*160 grams of oxygen}{44 grams of propane}$

mass of oxygen= 26.18 grams

But 26.18 moles of O₂ are not available, 12.5 grams are available. Since you have less mass than you need to react with 7.2 grams of propane, oxygen O₂ will be the limiting reagent.

Then you can apply the following rule of three: if by stoichiometry of the reaction 160 grams of oxygen form 132 grams of carbon dioxide, 12.5 grams of oxygen will form how much mass of carbon dioxide?

$mass of carbon dioxide=\frac{12.5 grams of oxygen*132 grams of carbon dioxide}{160 grams of oxygen}$

mass of carbon dioxide= 10.3125 grams

10.3125 grams of carbon dioxide will be formed.

7 0

2 years ago

.Find the pH if the [H3O+1] is 6.2  10-10 M

pishuonlain [190]

Answer:

The pH is 9,21.

Explanation:

The pH indicates the acidity or basicity of a substance. PH values between 0 and less than 7 indicate acidic solutions, 7 neutral and higher than 7 to 14 basic. It is calculated as

pH = -log (H 30+)

pH= -log (6,2 x 10^-10)

pH=9,21

3 0

2 years ago

A 475 cm3 sample of gas at standard temperature and pressure is allowed to expand until it occupies a

Andrej [43]

The final temperature : 345 K

<h3> Further explanation </h3>

Given

475 cm³ initial volume

600 cm³ final volume

Required

The final temperature

Solution

At standard temperature and pressure , T = 273 K and 1 atm

Charles's Law :

When the gas pressure is kept constant, the gas volume is proportional to the temperature

V₁/T₁=V₂/T₂

Input the value :

T₂=(V₂T₁)/V₁

T₂=(600 x 273)/475

T₂=345 K

4 0

2 years ago

Does the temperature of the solvent (water) affect the rate of dissolving?

gregori [183]

Yes. Heating up the solvent gives the molecules more kinetic energy. The more rapid motion means that the solvent molecules collide with the solute with greater frequency and the collisions occur with more force. Both factors increase the rate at which the solute dissolves.

3 0

2 years ago