1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
dlinn [17]
3 years ago
8

What are the characteristics of a substance in the gas phase?

Chemistry
1 answer:
3241004551 [841]3 years ago
5 0
<span>Anything in the gas phase has these characteristics: the particles are far apart and has indefinite shape and volume. Hope this helps you:)

</span>
You might be interested in
How many liters of 0.1107 M KCI contains 15.00 g of KCI (FW= 74.6 g/mol)
Mashcka [7]
Number of moles:

n = sample mass / molar mass

n = 15.00 / 74.6

n = 0.2010 moles of KCl

Therefore:

Molarity = moles / Volume

0.1107 = 0.2010 / V

V = 0.2010 / 0.1107

V = 1.815 L 


8 0
3 years ago
Read 2 more answers
Is c2h2 polar or non polar?
Lyrx [107]

Answer:

polar beacuse there is no way its non polar.

3 0
3 years ago
Read 2 more answers
A 10.4 g sample of CaSO4 is found to contain 3.06 g of Ca and 4.89 g of O. Find the mass of sulfur in a sample of CaSO4 with a m
andrey2020 [161]

The mass of sulfur in a sample of CaSO4 with a mass of 65.8 g is 15.50g.

<h3>How to calculate mass of an element in a compound?</h3>

According to this question, a 10.4 g sample of CaSO4 is found to contain 3.06 g of Ca and 4.89 g of O.

This means that the mass of sulfur in the 10.4g of CaSO4 is 10.4g - (3.06g + 4.89g) = 10.4g - 7.95g = 2.45g

Next, we calculate the percent ratio of each element in the compound; CaSO4.

  • Ca = 3.06g/10.4g × 100 = 29.42%
  • S = 2.45g/10.4g × 100 = 23.56%
  • O = 4.89g/10.4g × 100 = 47.02%

According to this question, a sample of CaSO4 with a mass of 65.8 g is given. The mass of each element in this compound is as follows:

  • Ca = 29.42/100 × 65.8g = 19.36g
  • S = 23.56/100 × 65.8g = 15.50g
  • O = 47.02/100 × 65.8g = 30.94g

Therefore, the mass of sulfur in a sample of CaSO4 with a mass of 65.8 g is 15.50g.

Learn more about mass at: brainly.com/question/13672279

#SPJ1

5 0
2 years ago
Graduated cylinder is filled to 41.5mL with water, and a price of granite is placed in the cylinder displacing the level to 47.6
Y_Kistochka [10]

Answer:

6.1 cm³

Explanation:

To solve this problem we first need to keep in mind <em>Archimedes' principle</em>:

  • The volume of water (or any fluid) displaced by a submerged object is equal to the object's volume.

With that in mind we <u>calculate the volume of the granite piece in mililiters</u>:

  • Volume displaced = 47.6 mL - 41.5 mL = 6.1 mL
  • Volume of the granite piece = 6.1 mL

Given that one cubic centimeter is equal to one mililiter, the volume of the granite piece in cm³ is 6.1 cm³.

8 0
3 years ago
WRITE THE ELECTRONIC CONFIGURATION OF THE FOLLOWING ELEMENT
Sunny_sXe [5.5K]
1 Hydrogen 1s1
2 Helium 1s2
3 Lithium 2s1
5 0
2 years ago
Read 2 more answers
Other questions:
  • Given that you added 5 ug of a purified acid phosphatase to tube a, calculate the amount of acid phosphatase (in ug) that was pr
    10·1 answer
  • PLEASE HELP ME ILL GIVE YOU A LOT OF POINTS
    9·1 answer
  • The combustion of octane, C8H18, proceeds according to the reaction
    13·2 answers
  • What happens to a person's weight on smaller and larger planets?
    14·1 answer
  • Calcium carbonate () is 34.5% Ca by mass. In a 418 g sample of , how many grams of calcium are present?
    9·1 answer
  • Why are models used for understanding cells
    14·1 answer
  • Can anybody help me? What is Oxidation? I used google but it didn't give me a good answer...
    6·1 answer
  • Please help is for my final An example of a chemical change is-
    6·1 answer
  • Assesses the consistency of observations by different observers.
    13·1 answer
  • Consider the reaction Cu + AgNO3 Ag + CUNO3 Which element is reduced? Which element is the oxidizing agent?​
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!