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kati45 [8]
2 years ago
6

Rocks are classified as igneous, sedimentary, or metamorphic based primarily on

Chemistry
1 answer:
irinina [24]2 years ago
7 0

Answer:

Method of formation

Explanation:

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When the volume of a gas is
Cerrena [4.2K]

Answer:

THE NEW VOLUME OF THE GAS IS 406 mL WHEN THE TEMPERATURE CHANGES FROM 765 K TO 315 K.

Explanation:

When the temperature changes from  765 K to 315K, the volume has changed from 986 mL to?

V1 = 986 mL = 0.986 L

T1 = 765 K

T2 = 315 K

V2 = unknown

Using Charles' equation of gas laws;

V1 / T1 = V2 / T2

Making V2 the subject of the formula:

V2 = V1 T2 / T1

V2 = 0.986 * 315 / 765

V2 = 0.406 L

V2 = 406 mL

So therefore, the volume of a gas changes from 986 mL to 406 mL as a result of a change in temperature from 765 K to 315 K.

7 0
3 years ago
Which statement accurately describes how electrical power and voltage are
neonofarm [45]

Answer: B

Explanation:

According to Ohm's Law, the answer is B.

Ohm's Law states that power is equal to volume x current.

If volume x current equals power, that means they are both 50% of power.

Ohm's Law:

power = voltage x current

current = voltage x power

voltage = power x current

I hope this answer helped.

7 0
3 years ago
Read 2 more answers
What does a pH of 7 say about a solution?
lisov135 [29]

Answer:

B

Explanation:

it shows that the solution is neutral.

I hope this helps

4 0
3 years ago
A wooden tool is found at an archaeological site. Estimate the age of the tool using the following information: A 100 gram sampl
lord [1]

Answer:

2578.99 years

Explanation:

Given that:

100 g of the wood is emitting 1120 β-particles per minute

Also,

1 g of the wood is emitting 11.20 β-particles per minute

Given, Decay rate = 15.3 % per minute per gram

So,

Concentration left can be calculated as:-

C left = [A_t]=\frac{11.20\ per\ minute}{15.3\ per\ minute\ per\ gram}\times [A_0]= 0.7320[A_0]

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

Also, Half life of carbon-14 = 5730 years

t_{1/2}=\frac {ln\ 2}{k}

Where, k is rate constant

So,  

k=\frac {ln\ 2}{t_{1/2}}

k=\frac {ln\ 2}{5730}\ years^{-1}

The rate constant, k = 0.000120968 year⁻¹

Time =?

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

So,  

\frac {[A_t]}{[A_0]}=e^{-0.000120968\times t}

\frac {0.7320[A_0]}{[A_0]}=e^{-0.000120968\times t}

0.7320=e^{-0.000120968\times t}

ln\ 0.7320=-0.000120968\times t

<u>t = 2578.99 years</u>

8 0
3 years ago
A flask contains a mixture of hydrogen gas and water vapor at STP. If the pressure of the water vapor is 19.5 mmHg, then what is
horrorfan [7]

Answer:

I would say A but not sure

Explanation:

7 0
2 years ago
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