Electronegativity is the tendency of an element to attract the bonded electrons towards itself. In a group, as the atomic radius increases electronegativity decreases as the outermost electron is far away from the nuclear attraction. In a period, the atomic size decreases. So, the effective nuclear charge experienced by the outermost shell increases. Therefore, across a period the electronegativity increases as the increased effective nuclear charge leads to the attraction of bonded electrons with greater ease.
Therefore the correct answer is <u>c</u>, electronegativity tends to increases across a period.
The question is incomplete. Complete question is read as:
'<span>One cup of fresh orange juice contains 115 mg of ascorbic acid (vitamin C, C6H8O6). Given that one cup = 218.0 mL calculate the molarity of vitamin C in organic juice.'
..........................................................................................................................
Answer:
Given: weight of solute (ascorbic acid) = 115 mg = 0.115 g
Volume of solution = 218.0 mL = 0.218 L
Molecular weight of ascorbic acid = 176.12 g/mol.
Now, Molarity = </span>

=

<span> =
0.002995 mol/dm3Answer: Molarity of solution = </span>
0.002995 mol/dm3<span>
</span>
It is what form where all coeficients are made into the smallest whole numbers
example
2C+4HC=8HC could be simplified to
C+2HC=4HC (note: formula is not a liegit one, only for example)
Answer:
[KOH] = 7.76×10⁻³ M
[Ca(OH)₂] = 2.39×10⁻³ M
Explanation:
KOH → K⁺ + OH⁻
pH = - log [H⁺]
14 = pH + pOH
pOH = - log [OH⁻]
10^-pOH = [OH⁻]
14 - 11.89 = 2.11 → pOH
2.11 = - log [OH⁻]
10⁻²°¹¹ = [OH⁻] → 7.76×10⁻³ M
As ratio is 1:1, [KOH] = 7.76×10⁻³ M
14 - 11.68 = 2.32 → pOH
10⁻²°³² = [OH⁻] → 4.78×10⁻³ M
Ca(OH)₂ → Ca²⁺ + 2OH⁻
Ratio is 2:1, so I will have the half of base.
4.78×10⁻³ /2 = 2.39×10⁻³ M
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