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saveliy_v [14]
3 years ago
14

Which substance can be decomposed by chemical means?

Chemistry
1 answer:
aliya0001 [1]3 years ago
6 0
Aluminum of course BriBri..
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Give the chemical symbols for the following elements: (a) potassium, (b) tin, (c) chromium, (d) boron,(e) barium, (f) plutonium,
Ilia_Sergeevich [38]

Answer:

A) Alkili Metal

B) Basic Metal

C)  Transition Metal

D) Semimetal

E) Alkiline Earth

F) Actinide

G) Nonmetal

H) Noble Gas

I) Transitional Metal  

Hope This Helps

8 0
4 years ago
Explain the difference between the reacts and products of a chemical reaction
Alika [10]
Reactants are what is changed in the chemical reaction. They go before the arrow when you wrote the equation. Products are what is formed when the chemical reaction occurs. Products always contain the same elements as the reactants, but they might be rearranged because of the reaction. In this picture, you can see that the reactants go before the arrow, and the products go after.

5 0
4 years ago
5. A gas has a pressure of 310 kPa at 237 degrees C.<br>What will its pressure be at 23 degrees C?)​
slavikrds [6]

Answer:

The pressure of the gas at 23 C is 179.92 kPa.

Explanation:

Gay-Lussac's law indicates that, as long as the volume of the container containing the gas is constant, as the temperature increases, the gas molecules move faster. Then the number of collisions with the walls increases, that is, the pressure increases. That is, the pressure of the gas is directly proportional to its temperature.

In short, when there is a constant volume, as the temperature increases, the pressure of the gas increases. And when the temperature is decreased, the pressure of the gas decreases.

Gay-Lussac's law can be expressed mathematically as follows:

\frac{P}{T} =k

Studying two states, one initial 1 and the other final 2, it is satisfied:

\frac{P1}{T1} =\frac{P2}{T2}

In this case:

  • P1= 310 kPa
  • T1= 237 C= 510 K (being 0 C= 273 K)
  • P2= ?
  • T2= 23 C= 296 K

Replacing:

\frac{310 kPa}{510 K} =\frac{P2}{296 K}

Solving:

P2=296 K*\frac{310 kPa}{510 K}

P2= 179.92 kPa

<u><em>The pressure of the gas at 23 C is 179.92 kPa.</em></u>

5 0
3 years ago
DNA<br> What organism is often used to study mutations
bezimeni [28]

Answer:

Hartwell's yeast

Explanation: A model organism for studying somatic mutations and cancer."

6 0
3 years ago
What’s the solution?
emmasim [6.3K]

Answer:

See balanced equations below

Explanation:

1. Mg(s) +2 HCL (aq) →MgCl₂ (aq) +H₂(g)

This is a single replacement reaction, involving an acid with a metal

2. 2Al(s) + 3H₂SO₄ (aq)→Al₂(SO₄)₃(aq) + 3H₂

3. 3 Zn (s) + 2H₃PO₄(aq)→ Zn₃(PO₄)₂ (aq) + 3H₂ (g)

4. 2Al(s) + 6HCL (aq)→2AlCl₃(aq) +3H₂ (g)

B.

1. 2KOH(aq) + MgCl₂→Mg(OH)₂ (aq) + 2KCl (aq)

2. 3NaOH (aq)+ Al(NO₃)₃ (aq)→Al(OH)₃(s) + 3 NaNO₃(aq) ---this is a precipitation reaction

3. BaBr₂(aq) + H₂SO₄→BaSO₄ (s) + 2Br⁻(aq)

4. Na₂S + 2HCl → 2NaCl (aq) + H₂S (g)

5. 3CaCl₂ +2K₃PO₄→ Ca₃(PO₄)₂+6KCl

6.Ba(NO₃)₂ + (NH₄)₂CO₃→ 2(NH₄)⁺(aq) +BaCO₃(s)

6 0
3 years ago
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