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olga2289 [7]
3 years ago
13

I need a Help plz! It’s my final exam!

Chemistry
1 answer:
LekaFEV [45]3 years ago
7 0
Um i think gold... i think?
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3 years ago
If you have 16 g of manganese (II) nitrate tetrahydrate, how much water is required to prepare 0.16 M solution from this amount
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<u>Answer:</u> The amount of water required to prepare given amount of salt is 398.4 mL

<u>Explanation:</u>

To calculate the volume of solution, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

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Putting values in above equation, we get:

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Volume of water = Volume of solution = 398.4 mL

Hence, the amount of water required to prepare given amount of salt is 398.4 mL

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3 years ago
You are building a uniform to protect workers from all types of nuclear radiation. If you use material that blocks _____ radiati
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What is the mass of 3.50 moles of Ba(NO2)2?
Fofino [41]

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  802.69 g

Explanation:

The molar mass of Barium nitrite is 229.34 g/mol, so 3.5 moles of it will have a mass of ...

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8 0
3 years ago
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