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4 years ago

If there are 2 numbers outside the parentheses in the distributive property which one do u distribute

Mathematics

1 answer:

Alex_Xolod [135]4 years ago

3 0

They always say to do the problem in parentheses first

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30 divided by 14 written as a fraction

svp [43]

Answer:

I believe your answer is 15/7

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2 years ago

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Integral pls i couldnt

olga nikolaevna [1]

Simplify the integrand:

$\dfrac{4x^4 + 3x^2 + 5x}{x^2} = 4x^2 + 3 + \dfrac5x$

Now integrate one term at a time.

$\displaystyle \int 4x^2 \, dx = \frac43 x^3 + C$

$\displaystyle \int 3 \, dx = 3x + C$

$\displaystyle \int \frac5x \, dx = 5 \ln|x| + C$

Putting everything together,

$\displaystyle \int \frac{4x^4 + 3x^2 + 5x}{x^2} \, dx = \int \left(4x^2 + 3 + \frac5x\right) \, dx = \boxed{\frac43 x^3 + 3x + 5 \ln|x| + C}$

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2 years ago

The measure of an angle is 15 degrees what is the measure of its supplementary angle?

Phantasy [73]

Answer:

165

Step-by-step explanation:

180-15=165

6 0

3 years ago

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Consider the following function. f(x) = 9 − x2/3 Find f(−27) and f(27). f(−27) = f(27) = Find all values c in (−27, 27) such tha

oksano4ka [1.4K]

I guess the function is $f(x)=9-x^{2/3}$ . Then $f(-27)=0$ and $f(27)=0$ .

The derivative is $f'(x)=-\dfrac23 x^{-1/3}$ , but there is no $c$ such that

$-\dfrac23c^{-1/3}=0$

This doesn't contradict Rolle's theorem because $f'(0)$ does not exists. In other words, $f$ is not differentiable on (-27, 27), so the conditions of Rolle's theorem are not met. (Looks like that would be the last option, or the second to last option if the last one is "Nothing can be concluded")

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3 years ago

I need help to find the x

Arada [10]

Answer:

34? (I don't know what the upper right corner says)

Step-by-step explanation:

6 0

2 years ago