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Hoochie [10]
3 years ago
12

The difference between the initial (first) position and the final position of an object

Chemistry
1 answer:
Anna [14]3 years ago
3 0
It is called DISPLACEMENT of the object....
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When an element exists in nature by itself, it must have a charge of
Fiesta28 [93]
H2O or water, all humans are mostly mad of water and water covers most of the earth 

7 0
3 years ago
A hydrogen filled balloon has a volume of 8.3 L at 36°C and 751 mmHg. How many moles of hydrogen are inside the balloon?
tamaranim1 [39]

Answer: I think the formula is PV=nRT and I divide both sides by RT, but this is as far as I can get in my equation before I get stumped: (751 mm Hg) (8.3 L)/ (309 K) Can you help?

Explanation:

8 0
3 years ago
A tank is filled with gasoline to a depth of exactly 2 feet. The tank is a cylinder resting horizontally on its side, with its c
inna [77]

Answer:

The volume of the gasoline in the tank is 18.85 cubic feet

Explanation:

The tank is a cylinder. The equation for calculating the cylinder volumen is πr²*h, r is radius and h is height. π is approximately 3.1416. So,  The tank is  resting horizontally on its side, its radius is 2 feet/2= 1 feet. h=a tank long= 6 feet.

With equation:

Vol gasoline=3.1416*1²*6=18.85 feet ³

I hope my answer helps you

6 0
3 years ago
What is the volume of 1.60 grams of O2 gas at STP? (5 points)
tiny-mole [99]

Answer:

  • <u><em>1.12 liters</em></u>

Explanation:

<u>Calculating number of moles</u>

  • Molar mass of O₂ = 32 g
  • n = Given weight / Molar mass
  • n = 1.6/32
  • n = 0.05 moles

<u>At STP</u>

  • One mole of O₂ occupies 22.4 L
  • Therefore, 0.05 moles will occupy :
  • 22.4 L x 0.05 = <u><em>1.12 L</em></u>
5 0
2 years ago
Read 2 more answers
What volume of 0.194 MNa3PO4 solution is necessary to completely react with 85.5 mL of 0.109 MCuCl2 ?
ira [324]

Answer:

35.9 ml

Explanation:

Start with the balanced equation:

3CuCl2(aq)+2Na3PO4(aq)→Cu3(PO4)2(s)+6NaCl(aq)

This tells us that 3 moles of CuCI2 react with 2 moles Na3PO4-

∴  1 mole CuCl2 will react with 2/3 moles Na3PO4

We know that concentration = moles/volume i.e:

c= n/v

∴n=c×v

∴nCuCl2=0.107×91.01000=9.737×10−3

I divided by 1000 to convert ml to L

∴nNa3PO4=9.737×10−3×23=6.491×10−3

v=nc=6.491×10−30.181=35.86×10−3L

∴v=35.86ml

4 0
2 years ago
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