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Hoochie [10]
3 years ago
12

The difference between the initial (first) position and the final position of an object

Chemistry
1 answer:
Anna [14]3 years ago
3 0
It is called DISPLACEMENT of the object....
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Halppp can anyone come up with a slogan for anti smoking
PtichkaEL [24]

Answer:

"Your Choice: Liberation From Your Own Choices or Continue the Choice That Decreases Your Liberation."

Explanation:

Liberation is the freeing or release from something restraining you. In this case, smoking holds you back from doing the things you used to do.

It's not that creative, but I hope this is good enough for you! :D (don't smoke)

5 0
2 years ago
Measure and pour a half cup (8 tablespoons) of tap water into the small container. Measure and record the temperature of the wat
omeli [17]

Answer:

around 50–55 degrees.

Explanation:

I believe this would be it because chemical reactions haven't happened yet. This is the usual tempurature for tap water.  :)

4 0
3 years ago
Read 2 more answers
The number of moles in 4.27×10^22 particles of silver is
bazaltina [42]

Answer:

mol=0.0709mol

Explanation:

Hello,

In this since one mole equals 6.022x10²³ particles of silver by means of the Avogadro's number, we can compute the moles in 4.27x10²² particles as shown below:

mol=4.27x10^{22}particles*\frac{1mol}{6.022x10^{23}particles}\\\\mol=0.0709mol

Best regards.

3 0
3 years ago
I need help plz with the first question plz
Cloud [144]
Ok so put it in order
7 0
3 years ago
Which equation is set up correctly to determine the volume of a 1.5 mole sample of oxygen gas at 22°C and 100 kPa?
LenKa [72]

The volume could be calculated by using  <span>V = n RT / P </span>

In which V = Volume
n = number of Moles
R= The Gas constant
T = Temperature (ideally this would be in Kelvin, but i don't see it in the option)
P = Pressure


I believe the answer is

 <span>V = (1.5mol) (0.08205 L*kPa/K*mol) (22Celsius)/100 kPa 


</span>
6 0
3 years ago
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