Answer: 72.93 litres
Explanation:
Given that:
Volume of gas (V) = ?
Temperature (T) = 24.0°C
Convert 24.0°C to Kelvin by adding 273
(24.0°C + 273 = 297K)
Pressure (P) = 1.003 atm
Number of moles (n) = 3 moles
Molar gas constant (R) is a constant with a value of 0.0821 atm L K-1 mol-1
Then, apply ideal gas equation
pV = nRT
1.003 atm x V = 3.00 moles x 0.0821 atm L K-1 mol-1 x 297K
1.003 atm•V = 73.15 atm•L
Divide both sides by 1.003 atm
1.003 atm•V/1.003 atm = 73.15 atm•L/1.003 atm
V = 72.93 L
Thus, the volume of the gas is 72.93 litres
Answer:
The answer to your question is 2 molecules
Explanation:
Unbalanced chemical reaction
H₂(g) + N₂(g) ⇒ NH₃ (g)
Reactants Elements Products
2 H 3
2 N 1
Balanced chemical reaction
3H₂(g) + N₂(g) ⇒ 2NH₃ (g)
Reactants Elements Products
6 H 6
2 N 2
From the balanced chemical reaction we conclude that when 3 molecules of hydrogen react with one molecule of nitrogen, 2 molecules of ammonia will be formed.
Answer:
please mark as brainliest!!
Explanation:
// C++ program to print initials of a name
#include <bits/stdc++.h>
using namespace std;
void printInitials(const string& name)
{
if (name.length() == 0)
return;
// Since touuper() returns int, we do typecasting
cout << (char)toupper(name[0]);
// Traverse rest of the string and print the
// characters after spaces.
for (int i = 1; i < name.length() - 1; i++)
if (name[i] == ' ')
cout << " " << (char)toupper(name[i + 1]);
}
// Driver code
int main()
{
string name = "prabhat kumar singh";
printInitials(name);
return 0;
}
ZnCl2 is the chemical formula, hope this helps.
