Answer: 72 grams of
are needed to completely burn 19.7 g ![C_3H_8(g)](https://tex.z-dn.net/?f=C_3H_8%28g%29)
Explanation:
According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number
of particles.
To calculate the number of moles, we use the equation:
![\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20moles%7D%3D%5Cfrac%7B%5Ctext%7BGiven%20mass%7D%7D%7B%5Ctext%7BMolar%20mass%7D%7D)
Putting in the values we get:
![\text{Number of moles}=\frac{19.7g}{44g/mol}=0.45moles](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20moles%7D%3D%5Cfrac%7B19.7g%7D%7B44g%2Fmol%7D%3D0.45moles)
![C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g)](https://tex.z-dn.net/?f=C_3H_8%28g%29%2B5O_2%28g%29%5Crightarrow%203CO_2%28g%29%2B4H_2O%28g%29)
According to stoichiometry:
1 mole of
requires 5 moles of oxygen
0.45 moles of
require=
moles of oxygen
Mass of ![O_2=moles\times {\text {Molar mass}}=2.25\times 32=72g](https://tex.z-dn.net/?f=O_2%3Dmoles%5Ctimes%20%7B%5Ctext%20%7BMolar%20mass%7D%7D%3D2.25%5Ctimes%2032%3D72g)
72 grams of
are needed to completely burn 19.7 g ![C_3H_8(g)](https://tex.z-dn.net/?f=C_3H_8%28g%29)
Answer:
PubChem CID 16663
Structure Find Similar Structures
Chemical Safety Laboratory Chemical Safety Summary (LCSS) Datasheet
Molecular Formula C9H20
Synonyms 4-ETHYLHEPTANE 2216-32-2 Heptane, 4-ethyl- 4-ethyl-heptane 4-ethyl heptane
Explanation:
The melting and boiling point depend on the strength of the ihydrogen bonds. Hydrogen bonding will cause the higher the melting and boiling points because more energy is needed to break bonds between molecules.
Hydrogen bonds affect solubility in water, molecules with hydrogen bonds dissolve better in water.
<span>One atom of silicon can properly be combined in a compound with two atoms of oxygen.</span>
Balanced equation:
Ca(OH)2+H2SO4=CaSO4+2 H20<span />