Question

Blood flows through a section of a horizontal artery that is partially blocked by a deposit along the artery wall. As a hemoglobin molecule moves from the narrow region into the wider region, its speed changes from v2 = 0.800 m/s to v1 = 0.630 m/s. What is the change in pressure, P1 - P2, that it experiences? The density of blood is 1060 kg/m3.

Answer 1

Answer:

$\Delta P=128.843\ Pa$

Explanation:

given,                                

speed of blood = v₂ = 0.800 m/s

v₁ = 0.630 m/s            

density of blood = 1060 kg/m³          

Atmospheric pressure =  8.89 ✕ 10⁴ N/m²

Using  Bernoulli equation                  

$P_1 - P_2 = \dfrac{1}{2}\rho (v_2^2-v_1^2)$  

$\Delta P= \dfrac{1}{2}\rho (0.8^2-0.63^2)$            

$\Delta P= \dfrac{1}{2}\times 1060\times (0.8^2-0.63^2)$            

$\Delta P=128.843\ Pa$

the change of pressure is equal to $\Delta P=128.843\ Pa$