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yulyashka [42]
3 years ago
10

How is the evidence from a fire scene collected? What should be avoided?

Chemistry
2 answers:
timama [110]3 years ago
5 0
Fire scenes<span> are different than regular crime </span>scenes<span> because the </span>evidence<span> that was at the.</span>Evidence from a fire scene<span> is </span>collected<span> by being placed in an air-</span><span>airtight.Plastic bags </span>should be avoided<span> because they can produce dangerous gases</span>
sveticcg [70]3 years ago
3 0

Answer:

Explanation:

In fire and arson cases evidences like volatile fuel in the sediment debris can be collected. The debris should be collected in an air-tight container like tin or paint box and bottles so as to prevent the evaporation of the fuel. The type of fuel used for setting up the fire is an important evidence.

Plastic bags should not be used because the plastic can react with the fuel components and may react with the fuel components in debris and the evidence will become futile.

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A chemist adds 1.80L of a 1.1/molL aluminum chloride AlCl3 solution to a reaction flask. Calculate the millimoles of aluminum ch
amm1812

Answer:

2000 millimoles of AlCl₃

Explanation:

From the question given above, the following data were obtained:

Volume of solution = 1.8 L

Molarity of solution = 1.1 mol /L

Millmole of AlCl₃ =?

Next, we shall determine the number of mole of AlCl₃ in the solution.

This can be obtained as follow:

Volume of solution = 1.8 L

Molarity of AlCl₃ solution = 1.1 mol /L

Number of mole of AlCl₃ =?

Molarity = mole /Volume

1.1 = Number of mole of AlCl₃ / 1.8

Cross multiply

Number of mole of AlCl₃ = 1.1 × 1.8

Number of mole of AlCl₃ = 1.98 moles

Finally, we shall convert 1.98 moles to millimoles. This can be obtained as follow:

1 mole = 1000 millimoles

Therefore,

1.98 mole = 1.98 mole × 1000 millimoles / 1 mole

1.98 mole = 1980 millimoles

1.98 mole ≈ 2000 millimoles

Thus, the chemist added 2000 millimoles of AlCl₃

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Which term describes the composition of matter shown in Figure E?
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