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lara31 [8.8K]
3 years ago
10

1. Sulfuric acid is formed when sulfur dioxide gas reacts with oxygen gas and water. Write a balanced chemical equation for the

reaction. If 12.5 mol sulfur dioxide reacts, how many mol of sulfuric acid can be produced and how many moles of oxygen gas is needed
Chemistry
1 answer:
tekilochka [14]3 years ago
4 0

Answer:

1. Balanced chemical for the given chemical reaction is :

2SO_2(g) +O_2(g) +2H_2O(l) \rightarrow  2H_2SO_4(aq)

number of mole of sulphuric acid produced = 12.5 mol

number of mole of oxygen required=6.25 mol

Explanation:

1. Balanced chemical for the given chemical reaction is :

2SO_2(g) +O_2(g) +2H_2O(l) \rightarrow  2H_2SO_4(aq)

from above balanced equation it is clearly that ,

2 mole of sulpher dioxide gives 2 mole of sulphuric acid

1 mole of sulpher dioxide gives 1 mole of sulphuric acid

therefore,

12 .5 mole of sulpher dioxide will givs 12.5 mole of sulphuric acid

number of mole of sulphuric acid produced = 12.5 mol

2 mole of sulphur dioxide needs 1 mole of oxygen gas

so,

1 mole of sulphur dioxide needs 0.5 mole of oxygen gas

therefore 12.5 of sulphur dioxide needs 12.5 \times 0.5mole of oxygen

number of mole of oxygen required=6.25 mol

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A solution contains 15.27 grams of NaCl in 0.670 kg water at 25 °C. What is the vapor pressure of the solution?
Anvisha [2.4K]

Answer:

The vapor pressure of the solution is 23.636 torr

Explanation:

P_{solution} = X_{solvent}*P_{solvent}

Where;

P_{solution is the vapor pressure of the solution

X_{solvent is the mole fraction of the solvent

P_{solvent is the vapor pressure of the pure solvent

Thus,

15.27 g of NaCl = [(15.27)/(58.5)]moles = 0.261 moles of NaCl

0.67 kg of water =  [(0.67*1000)/(18)]moles = 37.222 moles of H₂O

Mole fraction of solvent (water) = (number of moles of water)/(total number of moles present in solution)

Mole fraction of solvent (water) = (37.222)/(37.222+0.261)

Mole fraction of solvent (water) = 0.993

<u>Note:</u> the vapor pressure of water at 25°C is 0.0313 atm

Therefore, the vapor pressure of the solution = 0.993 * 0.0313 atm

the vapor pressure of the solution = 0.0311 atm = 23.636 torr

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3 years ago
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T = 409.5 K, P = 1.50 atm: V = ?L
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Explanation:

T = 409.5 K, P = 1.50 atm: V = 22.4 L The ideal gas law is: PV = nRT where. P = pressure. V = volume n = number of moles.

7 0
3 years ago
Can you check this for me?
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Hi, your answer is correct.
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A certain compound is made up of two chlorine atoms, one carbon atom, and one oxygen atom. what is the chemical formula of this
Ostrovityanka [42]
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A compound has a percent composition of 38.7% carbon, 9.76% hydrogen, 51.5% oxygen.
goldenfox [79]

The molecular formula of the compound that has a percent composition of 38.7% carbon, 9.76% hydrogen, 51.5% oxygen is C2H6O2.

<h3>How to calculate molecular formula?</h3>

The molecular formula can be calculated from the empirical formula. The empirical formula of the compound is calculated as follows:

  • C = 38.7% = 38.7g
  • H = 9.76% = 9.76g
  • O = 51.5% = 51.5g

Next, we convert the mass to moles by dividing by their atomic mass:

  • C = 38.7 ÷ 12 = 3.23mol
  • H = 9.76 ÷ 1 = 9.76mol
  • O = 51.5÷ 16 = 3.22mol

Next, we divide by the smallest (3.22)

  • C = 1
  • H = 3
  • O = 1

Hence, the empirical formula of the compound is CH3O

If the molar mass of the compound is 62g/mol;

(CH3O)n = 62

31n = 62

n = 2

(CH3O)2 = C2H6O2

Therefore, the molecular formula of the compound that has a percent composition of 38.7% carbon, 9.76% hydrogen, 51.5% oxygen is C2H6O2.

Learn more about molecular formula at: brainly.com/question/14425592

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