The coefficient for hydrogen in the balanced equation of solid molybdenum(iV) oxide with gaseous hydrogen is 2
Explanation
Coefficient is defined to as a number in front of a chemical formula in a balanced chemical equation.
The reaction of molybdenum (iv) oxide with gaseous hydrogen is as below,
MoO2 + 2 H2→ Mo +2 H2O
From balanced equation above the coefficient for H2 is 2 since the number in front of H2 is 2
<span> </span> <span>V = nRT/P =
(0.875)(0.082057)(273)/(1) = 19.6 L</span>
Answer:
Option D. equation D
Explanation:
Positron is simply a beta plus decay or superscript 0 e subscription 1 (0 1 e).
Now, let us consider the options given:
Option A is emitting alpha decay
Option B is emitting beta minus decay.
Option C is emitting beta minus decay.
Option D is emitting beta plus decay also known as Positron.
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