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svetlana [45]
3 years ago
13

The reaction of nitrogen monoxide with ozone at 25 oC NO + O3NO2 + O2 is first order in NO and first order in O3. Complete the r

ate law for this reaction in the box below. Use the form k[A]m[B]n... , where '1' is understood for m, n ... (don't enter 1) and concentrations taken to the zero power do not appear. Rate =
In an experiment to determine the rate law, the rate constant was determined to be 109 M-1s-1. Using this value for the rate constant, the rate of the reaction when [NO] = 0.186 M and [O3] = 3.14×10-2 M would be [blank] Ms-1.
Chemistry
1 answer:
svetlana [45]3 years ago
4 0

Answer : The value of rate of reaction is 6.37\times 10^{-1}Ms^{-1}

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

The given chemical equation is:

NO+O_3\rightarrow NO_2+O_2

Rate law expression for the reaction is:

\text{Rate}=k[NO]^a[O_3]^b

As per question,

a = order with respect to NO  = 1

b = order with respect to O_3 = 1

Thus, the rate law becomes:

\text{Rate}=k[NO]^1[O_3]^1

\text{Rate}=k[NO][O_3]

Now, calculating the value of rate of reaction by using the rate law expression.

Given :

k = rate constant = 109M^{-1}s^{-1}

[NO] = concentration of NO = 0.186 M

[O_3] = concentration of [O_3] = 3.14\times 10^{-2}M

Now put all the given values in the above expression, we get:

\text{Rate}=(109M^{-1}s^{-1})\times (0.186M)\times (3.14\times 10^{-2}M)

\text{Rate}=6.37\times 10^{-1}Ms^{-1}

Hence, the value of rate of reaction is 6.37\times 10^{-1}Ms^{-1}

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<u>Answer:</u> 4.999 moles of excess reactant will be left over.

<u>Explanation:</u>

Limiting reagent is defined as the reagent which is completely consumed in the reaction and limits the formation of the product.

Excess reagent is defined as the reagent which is left behind after the completion of the reaction.

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}       .....(1)

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Putting values in equation 1:

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For the given chemical reaction:

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By the stoichiometry of the reaction:

2 moles of aluminium carbide reacts with 12 moles of water

So, 0.778 moles of aluminium carbide will react with = \frac{12}{2}\times 0.778=4.668 mol of water

Given mass of water = 174 g

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Putting values in equation 1:

\text{Moles of water}=\frac{174g}{18g/mol}=9.667mol

Moles of excess reactant (water) left = 9.667 - 4.668 = 4.999 moles

Hence, 4.999 moles of excess reactant will be left over.

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