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3 years ago

Current events and overexposure of sun

Physics

1 answer:

denis-greek [22]3 years ago

5 0

Answer:

"Over exposure of sun is not a very likely phenomeno, because it has been set up by likely something else (ie. greater) and the sun will is not accually warming the Earth more and more as the mass media would have you believe." (Paragraph 18 Section 9, Current or Not? Over Exposure of Sun, Page 13. (2019 edition))

Explanation:

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In Anchorage, collisions of a vehicle with a moose are so common that they are referred to with the abbreviationMVC. Suppose a 1

lara31 [8.8K]

Answer:

Part a)

$f = \frac{8}{9}$

Part b)

$f = \frac{120}{169}$

Part c)

So from above discussion we have the result that energy loss will be more if the collision occurs with animal with more mass

Explanation:

Part a)

Let say the collision between Moose and the car is elastic collision

So here we can use momentum conservation

$m_1v_{1i} = m_1v_{1f} + m_2v_{2f}$

$1000 v_o = 1000 v_{1f} + 500 v_{2f}$

also by elastic collision condition we know that

$v_{2f} - v_{1f} = v_o$

now we have

$2v_o = 2v_{1f} + v_o + v_{1f}$

now we have

$v_{1f} = \frac{v_o}{3}$

Now loss in kinetic energy of the car is given as

$\Delta K = \frac{1}{2}m(v_o^2 - v_{1f}^2)$

$\Delta K = \frac{1}{2}m(v_o^2 - \frac{v_o^2}{9})$

so fractional loss in energy is given as

$f = \frac{\Delta K}{K}$

$f = \frac{\frac{4}{9}mv_o^2}{\frac{1}{2}mv_o^2}$

$f = \frac{8}{9}$

Part b)

Let say the collision between Camel and the car is elastic collision

So here we can use momentum conservation

$m_1v_{1i} = m_1v_{1f} + m_2v_{2f}$

$1000 v_o = 1000 v_{1f} + 300 v_{2f}$

also by elastic collision condition we know that

$v_{2f} - v_{1f} = v_o$

now we have

$10v_o = 10v_{1f} + 3(v_o + v_{1f})$

now we have

$v_{1f} = \frac{7v_o}{13}$

Now loss in kinetic energy of the car is given as

$\Delta K = \frac{1}{2}m(v_o^2 - v_{1f}^2)$

$\Delta K = \frac{1}{2}m(v_o^2 - \frac{49v_o^2}{169})$

so fractional loss in energy is given as

$f = \frac{\Delta K}{K}$

$f = \frac{\frac{60}{169}mv_o^2}{\frac{1}{2}mv_o^2}$

$f = \frac{120}{169}$

Part c)

So from above discussion we have the result that energy loss will be more if the collision occurs with animal with more mass

8 0

3 years ago

Suppose a=3i-2j+k b=-i-4j+3k and c is avector lying along positive x axis with the property that a(b+c)=0 then find c?

il63 [147K]

The value of the c will be (0 i+0 j+0 k). c is a vector that is along the positive x-axis and has the condition a(b+c)=0.

<h3>What is a vector?</h3>

A vector is a quantity or phenomena with magnitude and direction that are independent of one another. The phrase also refers to a quantity's mathematical or geometrical representation.

Given ;

a=3i-2j+k

b=-i-4j+3k

Given property:

a(b+c)=0

-i-4j+3k ((-i-4j+3k)+c)=0

(3+8+3)(-i-4j+3k)c=0

14(-i-4j+3k)c=0

c=0 i+0 j+0 k

Hence, the value of the c will be (0 i+0 j+0 k).

To learn more about the vector refer to the link;

brainly.com/question/13322477

#SPJ1

6 0

2 years ago

If 5.7 grams of gold has 3 cubic centimeters than whats the density of gold in g/cm3

Aleonysh [2.5K]

Density: 1.9 g/cm3

density = mass/volume
d = 5.7/3
d = 1.9

3 0

3 years ago

A car is moving at 80km/h accelerates to pass a truck. Five seconds later the car is moving at 100km/h. What is the Acceleration

labwork [276]

Answer/Explanation:

Acceleration is the rate of change of the velocity of an object that is moving. This value is a result of all the forces that is acting on an object which is described by Newton's second law of motion. Calculation of such is straightforward, if we are given the final velocity, the initial velocity and the total time interval. We can just use the kinematic equations. Fortunately, we are given these values. So, we calculate as follows:

acceleration = v - v0 / t

acceleration = (80 mph - 50 mph) ( 1 h / 3600) / 5 s

acceleration = 1.67 x 10^-3 m / s^2

8 0

3 years ago

Read 2 more answers

If a car manufacturer reduced the mass of a new car model, so that it took a force of 4000 N

Sauron [17]

Answer:

1000 kg

Explanation:

Force = mass x acceleration, Hence, mass = Force/acceleration

mass = 4000/4 = 1000 kg

5 0

3 years ago