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Katen [24]
2 years ago
12

How would you find the speed of a person who walked

Physics
1 answer:
Alex Ar [27]2 years ago
4 0

Answer:

v = 1.25 m/s

Explanation:

We have,

Distance covered by a person is 10 meters

Time taken by him to cover that distance is 8 seconds.

If we want to find the speed of a person, we must know distance covered by it and taken. In this case, we know both distance and time. His speed is given by :

v=\dfrac{d}{t}\\\\v=\dfrac{10\ m}{8\ s}\\\\v=1.25\ m/s

So, the speed of the person is 1.25 m/s.

You might be interested in
Which law states that the pressure and absolute temperature of a fixed quantity of gas are directly proportional under constant
Brrunno [24]

<u>Gay Lussac’s law</u> state that the pressure and absolute temperature of a fixed quantity of a gas are directly proportional under constant volume conditions.  

<h2>Further Explanation </h2><h3>Gay-Lussac’s law  </h3>
  • It states that at constant volume, the pressure of an ideal gas I directly proportional to its absolute temperature.
  • Thus, an increase in pressure of an ideal gas at constant volume will result to an increase in the absolute temperature.
<h3>Boyles’s law   </h3>
  • This gas law states that the volume of a fixed mass of a gas is inversely proportional to its pressure at constant absolute temperature.
  • Therefore, when the volume of an ideal gas is increased at constant temperature then the pressure of the gas will also increase.
<h3>Charles’s law </h3>
  • It states that the volume of a fixed mass of a gas is directly proportional to absolute temperature at constant pressure.
  • Therefore, an increase in volume of an ideal gas causes a corresponding increase in its absolute temperature and vice versa while the pressure is held constant.
<h3>Dalton’s law  </h3>
  • It is also known as the Dalton’s law of partial pressure. It states that the total pressure of a mixture of gases is always equivalent to the total sum of the partial pressures of individual component gases.
  • Partial pressure refers to the pressure of an individual gas if it occupies the same volume as the mixture of gases.

Keywords: Gas law, Gay-Lussac’s law, pressure, volume, absolute temperature, ideal gas

<h3>Learn more about: </h3>
  1. Gay-Lussac’s law: brainly.com/question/2644981
  2. Charles’s law: brainly.com/question/5016068
  3. Boyles’s law: brainly.com/question/5016068
  4. Dalton’s law: brainly.com/question/6491675

Level: High school  

Subject: Chemistry  

Topic: Gas laws  

Sub-topic: Gay-Lussac’s law  

8 0
3 years ago
Read 2 more answers
If the v – t graph of a particle is parallel to the t – axis the body has (a) uniform velocity (b) uniform acceleration (c) zero
maxonik [38]

Answer:

zero  velocity

Explanation:

if the v-t graph is parallel to the time axis its mean body has covered no path in other words the body is at rest so the velocity of the body should be zero

hope my answer will helps u plz mark me brainlist

5 0
2 years ago
(20 points) You are at the center of a boat and have been rowing the boat for a long time. You weigh only 80 kg and your 120 kg
valina [46]

Answer:

Explanation:

From the given information:

Let the first weight be m_ 1 = 80 kg

The weight of the buddy be m_2 = 120 kg

The weight of  Bubba be m_3 = 60 kg

Also, since you and Budda are a distance of 4m to each other, then the length to which both meet buddy will be:

x_1 = x_3 = \dfrac{4}{2} \\ \\ = 2

The length of the boat be x_2 = 4 m

∴

We can find the center of mass of the system by using the formula:

X_{CM} = \dfrac{m_1x_1+m_2x_2+m_3x_3}{m_1+m_2+m_3} \\ \\ X_{CM} = \dfrac{(80 \times 2)+(120\times4)+(60\times2)}{80+120+60} \\ \\ X_{CM} = \dfrac{160+480+120}{260} \\ \\ \mathbf{X_{CM} = 2.923}

4 0
2 years ago
A 1 036-kg satellite orbits the Earth at a constant altitude of 98-km. (a) How much energy must be added to the system to move t
Veronika [31]

Answer:

a) The Energy added should be 484.438 MJ

b) The  Kinetic Energy change is -484.438 MJ

c) The Potential Energy change is 968.907 MJ

Explanation:

Let 'm' be the mass of the satellite , 'M'(6×10^{24} be the mass of earth , 'R'(6400 Km) be the radius of the earth , 'h' be the altitude of the satellite and 'G' (6.67×10^{-11} N/m) be the universal constant of gravitation.

We know that the orbital velocity(v) for a satellite -

v=\sqrt{\frac{Gmm}{R+h} }         [(R+h) is the distance of the satellite   from the center of the earth ]

Total Energy(E) = Kinetic Energy(KE) + Potential Energy(PE)

For initial conditions ,

h = h_{i} = 98 km = 98000 m

∴Initial Energy (E_{i})  = \frac{1}{2}mv^{2} + \frac{-GMm}{(R+h_{i} )}

Substituting v=\sqrt{\frac{GMm}{R+h_{i} } } in the above equation and simplifying we get,

E_{i} = \frac{-GMm}{2(R+h_{i}) }

Similarly for final condition,

h=h_{f} = 198km = 198000 m

∴Final Energy(E_{f}) = \frac{-GMm}{2(R+h_{f}) }

a) The energy that should be added should be the difference in the energy of initial and final states -

∴ ΔE = E_{f} - E_{i}

        = \frac{GMm}{2}(\frac{1}{R+h_{i} } - \frac{1}{R+h_{f} })

Substituting ,

M = 6 × 10^{24} kg

m = 1036 kg

G = 6.67 × 10^{-11}

R = 6400000 m

h_{i} = 98000 m

h_{f} = 198000 m

We get ,

ΔE = 484.438 MJ

b) Change in Kinetic Energy (ΔKE) = \frac{1}{2}m[v_{f} ^{2} - v_{i} ^{2}]

                                                          = \frac{GMm}{2}[\frac{1} {R+h_{f} } - \frac{1} {R+h_{i} }]

                                                          = -ΔE                                                            

                                                          = - 484.438 MJ

c)  Change in Potential Energy (ΔPE) = GMm[\frac{1}{R+h_{i} } - \frac{1}{R+h_{f} }]

                                                             = 2ΔE

                                                             = 968.907 MJ

3 0
3 years ago
What type of force are you exerting when you lie on a bed
zysi [14]

Answer:

Compression is the answer

Explanation:

got it right

6 0
3 years ago
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