C. 15Ω.
The circuit diagram is shown in the first image attached. To solve this problem we have to use the equivalent resistor conected in parallel Req = (R1*R2)/(R1+R2).
Calculating the equivalent resistor in the 20Ω resistor parallel arrangement:
RAeq = [(20*20)/(20+20)] Ω
RAeq = 400/40 Ω
RAeq = 10Ω
Calculating the equivalent resistor in the 10Ω resistor parallel arrangement:
RBeq = [(10*10)/(10+10)]Ω
RBeq = 100/20 Ω
RBeq = 5Ω
Both equivalent resistors are in series. So, in order to calculate the equivalent resistance of the combination:
Rtotal = RAeq + RBeq
Rtotal = 10Ω + 5Ω
Rtotal = 15Ω
Answer:
Even though the cross-sectional area of each capillary is extremely small compared to that of the large aorta, the total cross-sectional area of all the capillaries added together is about 1,300 times greater than the cross-sectional area of the aorta because there are so many capillaries
Explanation:
Operant conditioning, sometimes called <em>instrumental learning</em>, was first extensively studied by Edward L. Thorndike, who observed the behavior of cats trying to escape from home-made puzzle boxes.
Hope this helps!
when they all are opisite
IDK I just guess
M1 = 750Kg, v1 = 10m/s
m2 = 2500Kg , v2= 0 (because in problem say cuz that object don t move).
The momentum before colision is equal with the momentum after colision:
m1v1 + m2v2 = (m1+m2)v3 => v3 is the velocity after colison and that s u want to caluclate for your problem
=> m1v1 = (m1+m2)v3 => v3 = m1v1/(m1+m2) now u should do the math i think v3 prox 2,4 but not sure u should caculate
