1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Bad White [126]
3 years ago
14

Assume that an oil slick consists of a single layer of molecules and that each molecule occupies a cube 0.488 nm on a side. dete

rmine the area of an oil slick formed by 0.708 m3 of oil. answer in units of m2 .
Chemistry
1 answer:
IgorC [24]3 years ago
5 0
<span>Since the oil slick consists of a single layer, then the thickness of the oil slick is 0.488 nm. When we multiply the thickness of the oil slick by the area A, then we should get the volume of the oil slick 0.708 m^3. We can set up an equation to find the area A. (A)(0.488 nm) = 0.708 m^3 A = 0.708 m^3 / 0.488 nm A = 0.708 m^3 / 0.488 X 10^{-9} m A = (0.708 / 0.488) X 10^9 m^2 A = 1.45 X 10^9 m^2 The area of the oil slick is 1.45 X 10^9 m^2</span>
You might be interested in
A balloon contains 2.0 L of air at 101.5 kPa . You squeeze the balloon to a volume of 0.25 L.
8_murik_8 [283]
<h3>Answer:</h3>

812 kPa

<h3>Explanation:</h3>
  • According to Boyle's law pressure and volume of a fixed mass are inversely proportional at constant absolute temperature.
  • Mathematically, P\alpha \frac{1}{V}

At varying pressure and volume;

P1V1=P2V2

In this case;

Initial volume, V1 = 2.0 L

Initial pressure, P1 = 101.5 kPa

Final volume, V1 = 0.25 L

We are required to determine the new pressure;

P2=\frac{P1V1}{V2}

Replacing the known variables with the values;

P2=\frac{(101.5)(2.0L)}{0.25L}

           = 812 kPa

Thus, the pressure of air inside the balloon after squeezing is 812 kPa

8 0
3 years ago
Which is larger? C atom or F atom? Explain why.
tekilochka [14]

Answer:

Carbon or Fleuronie?

Explanation:

3 0
3 years ago
A galvanic cell at a temperature of 25.0°C is powered by the following redox reaction:
soldi70 [24.7K]

Answer:

2.01V ( To three significant digits)

Explanation:

First we show the standard reduction potentials of Cu2+(aq)/Cu(s) system and Al3+(aq)/Al(s) system. We can clearly see from the balanced redox reaction equation that aluminium is the anode and was the oxidized specie while copper is the cathode and was the reduced specie. This observation is necessary when substituting values of concentration into the Nernst equation.

The next thing to do is to obtain the standard cell potential as shown in the image attached and subsequently substitute values of concentration and standard cell potential into the Nernst equation as shown. This gives the cell potential under the given conditions.

5 0
3 years ago
Classify each chemical compound listed in the table below.
prisoha [69]

Answer:

Please find attached the table of classification of the chemical compounds, created with Microsoft Word

Explanation:

The given compounds are;

H₂SO₃ is an acid which is known as sulfurous acid

When SO₂ is added to water, we have;

SO₂ + H₂O ⇄ HSO₃ + H⁺

Therefore, H₂SO₃ is ionic

2) HI which is known as hydrogen iodide, dissolves in water as follows

HI (g) + H₂O (l)  ⇄ H₃O⁺(aq) + I⁻(aq)

Therefore, HI is able to donate hydrogen ions therefore, it is both acidic and ionic

3) KI is a salt of the alkali metal, potassium, and iodine which is a group 7 element such that it formed by the transfer of electrons from potassium to iodine making it an ionic compound

KI forms a slightly alkaline solution

4) NaClO₃ comprises of the ionic combination of sodium and chlorate ions which dissolves in water as follows;

NaClO₃ → Na⁺(aq) + ClO₃⁻(aq)

Therefore, NaClO₃ is ionic

NaClO₃ is also a strong oxidizing agent, making a Br∅nsted acid

we have;  

Sulfurous acid (also Sulfuric(IV) acid, Sulphuric acid (UK), Sulphuric(IV) acid (UK)) is the chemical compound with the formula H2SO3. There is no evidence that sulfurous acid exists in solution, but the molecule has been detected in the gas phase.[1] The conjugate bases of this elusive acid are, however, common anions, bisulfite (or hydrogen sulfite) and sulfite.

4 0
3 years ago
Find ΔG° for the reactions in Problem 20.51 using ΔHf° and S° values.
pashok25 [27]

The value of ΔG° (gibbs free energy change)of the given reaction is -1131.94kj .

Given ,

Balanced chemical equation is given by,

2Mg(s) + O2 (g) → 2MgO (s)

Here , the standard enthalpy of Mg  and O2 gas are zero because they are in the most stable state .

thus , the value of ΔG°rxn is given by ,

ΔG°rxn = ΔG°(products ) - ΔG°(reactants )

ΔG°rxn = [2×(-565.97 )] - 0

ΔG°rxn = 2×(-565.97)

ΔG°rxn = -1131.94kj

Hence , the value of ΔG° of the given reaction is -1131.94kj .

<h3>What is a balance chemical reaction ?</h3>

A balanced chemical reaction is a type of reaction which include the reactants and products in same amount i.e. the no of mole on both side of the reaction is remains same or balanced .

Learn more about chemical reaction here :

brainly.com/question/1893305

#SPJ4

Disclaimer :

incomplete question . here is the complete question .

Question :

Calculate ΔG° for the reaction using ΔG°f values :

2Mg(s) + O2 (g) → 2MgO (s)

Find the ΔG° for the reaction using ΔH°f and S° values .

3 0
1 year ago
Other questions:
  • Whats the volume of 0.522 moles of carbine dioxide
    8·1 answer
  • Which statement explains why a C–O bond is
    7·2 answers
  • What is the air temperature 8,850 m in the air?
    7·1 answer
  • HELP PLEASE What about winter temperatures of 0 and -3? …………….% 28 and 15? ……………….%
    12·1 answer
  • Solid carbon and oxygen gas react to yield carbon dioxide gas. write the following balanced chemical equation. please help
    10·1 answer
  • Which statement is true of a
    9·1 answer
  • Complete the sentence: The greater the force that is applied to an object, the _____ the acceleration. However, if that same for
    8·2 answers
  • The weight of 112 liters of carbon dioxide at STP would be<br> 44.09.<br> True or false?
    9·1 answer
  • Prepare a project report on various samples of
    6·1 answer
  • In an experiment magnesium ribbon was heated in air. The product was found to be heavier than the original ribbon. Potassium man
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!