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Bad White [126]
3 years ago
14

Assume that an oil slick consists of a single layer of molecules and that each molecule occupies a cube 0.488 nm on a side. dete

rmine the area of an oil slick formed by 0.708 m3 of oil. answer in units of m2 .
Chemistry
1 answer:
IgorC [24]3 years ago
5 0
<span>Since the oil slick consists of a single layer, then the thickness of the oil slick is 0.488 nm. When we multiply the thickness of the oil slick by the area A, then we should get the volume of the oil slick 0.708 m^3. We can set up an equation to find the area A. (A)(0.488 nm) = 0.708 m^3 A = 0.708 m^3 / 0.488 nm A = 0.708 m^3 / 0.488 X 10^{-9} m A = (0.708 / 0.488) X 10^9 m^2 A = 1.45 X 10^9 m^2 The area of the oil slick is 1.45 X 10^9 m^2</span>
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1. (8pt) Using dimensional analysis convert 600.0 calories into kilojoules
Ivanshal [37]

Answer:

1. 2.510kJ  

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Explanation:

Hello there!

In this case, according to the given information for this calorimetry problem, we can proceed as follows:

1. Here, we consider the following equivalence statement for converting from calories to joules and from joules to kilojoules:

1cal=4.184J\\\\1kJ=1000J

Then, we perform the conversion as follows:

600.0cal*\frac{4.184J}{1cal}*\frac{1kJ}{1000J}=2.510kJ

2. Here, we use the general heat equation:

Q=mC(T_2-T_1)

And we plug in the given mass, specific heat and initial and final temperature to obtain:

Q=236g*0.24\frac{J}{g\°C} (34.9\°C-8.5\°C)\\\\Q=1495.3J*\frac{1kJ}{1000J} \\\\Q=1.5kJ

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6.94444

Explanation:

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