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KIM [24]
3 years ago
15

Determine the soil texture for the following combinations of sand, silt, and clay.

Chemistry
1 answer:
JulijaS [17]3 years ago
7 0

Answer:

a. Clay

b. Sandy Loam

c. Sandy Clay

d. Loamy Sand

Explanation:

Based on the soil texture triangle, the soil texture for the following combination of sand, silt and clay are;

a. Sand 20 percent; Silt 20 percent;Clay 60 percent: ____ CLAY

b. Sand 60percent; Silt 30percent; Clay 10percent: ___ SANDY LOAM

c. Sand 50percent; Silt 10percent;Clay 40 percent: ____ SANDY CLAY

d. Sand 80 percent; Silt 15 percent; Clay 5percent:_____ LOAMY SAND

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If the [H+] = 0.01 M, what is the pH of the solution, and is the solution a strong acid, weak acid, strong base, or weak base?
lana66690 [7]

Answer:

2, strong acid

Explanation:

Data obtained from the question. This includes:

[H+] = 0.01 M

pH =?

pH of a solution can be obtained by using the following formula:

pH = –Log [H+]

pH = –Log 0.01

pH = 2

The pH of a solution ranging between 0 and 6 is declared to be an acid solution. The smaller the pH value, the stronger the acid.

Since the pH of the above solution is 2, it means the solution is a strong acid.

5 0
3 years ago
If the hydroxide ion concentration of a solution is 3.26 x 10-6 M, is it an acidic or a basic solution?
sladkih [1.3K]

Answer: It is a basic solution with pH =8.51

Explanation:

We were given that hydroxide ion concentration [OH-] as 3.26 x 10-6 M

But We know thar

[OH-] [H+] = 1 × 10^-14

To get the Hydrogen ion [H+] concentration, we have that

[H+] = 1 × 10^-14 M/[OH-]

= 1 × 10^-14 M/3.26 x 10-6 M

    =  3.067 x 10^-9 M

But, pH = - log [H+]

Therefore,

pH = - log (3.067 x 10^-9)

pH=8.51

when  pH > 7, The solution is basic, therefore a solution with pH =8.51 is basic.

8 0
3 years ago
An analysis of a sugar compound is found to contain 132 grams of carbon (C), 22 grams of hydrogen (H), and 176 grams of oxygen (
ddd [48]
132 g of C  ,   22 g of H   , 176 g of O

132 + 22 + 176 => 330 g <span>of the substance

</span>Now convert the masses in <span>moles :
</span>
C = 12.0 u        H = 1.0 u       O = 16.0 u

C = 132 / 12.0 => 11 moles

H = 22 / 1.0 => 22 moles

O = 176 / 16.0 => 11 moles

Using the values obtained the lowest proportion in mols of elements present, simply divide the values found for the least of them<span>:
</span>
C = 11 / 11 => 1

H = 22 / 11 => 2

O = 11 / 11 => 1

 formula empirically <span>is : CH</span>₂O

hope this helps!


8 0
4 years ago
What is an example of the strong nuclear force?
Lina20 [59]

Here are two examples of strong nuclear force !

Protons and nucleons


I hope that's help !

5 0
4 years ago
What is the final volume?
zaharov [31]

Answer:

Option A. 9.4 L

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 8 L

Initial temperature (T₁) = 293 K

Final temperature (T₂) = 343 K

Final volume (V₂) =?

V₁ / T₁ = V₂ / T₂

8 / 293 = V₂ / 343

Cross multiply

293 × V₂ = 8 × 343

293 × V₂ = 2744

Divide both side by 293

V₂ = 2744 / 293

V₂ = 9.4 L

Therefore, the final volume of the gas is 9.4 L

6 0
3 years ago
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