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KIM [24]
3 years ago
15

Determine the soil texture for the following combinations of sand, silt, and clay.

Chemistry
1 answer:
JulijaS [17]3 years ago
7 0

Answer:

a. Clay

b. Sandy Loam

c. Sandy Clay

d. Loamy Sand

Explanation:

Based on the soil texture triangle, the soil texture for the following combination of sand, silt and clay are;

a. Sand 20 percent; Silt 20 percent;Clay 60 percent: ____ CLAY

b. Sand 60percent; Silt 30percent; Clay 10percent: ___ SANDY LOAM

c. Sand 50percent; Silt 10percent;Clay 40 percent: ____ SANDY CLAY

d. Sand 80 percent; Silt 15 percent; Clay 5percent:_____ LOAMY SAND

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Sulphur burnt in oxygen forms sulphur dioxide. Calculate the heat given out when 1.6g of sulphur is burnt.
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3 years ago
Which of the following has the strongest buffering capacity? A. H2O B. 0.1 M HCl C. 0.1 M carbonic/bicarbonate (H2CO3/HCO3-) at
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Explanation:

(A)   As we know that carbonic acid (H_{2}CO_{3}) and Sodium bicarbonate (NaHCO_{3}) forms an acidic buffer.

Therefore, pH of an acidic buffer is given by Hendeerson-Hasselbalch equation as follows.

               pH = pK_{a} + log(\frac{[Salt]}{[Acid]}) ........... (1)

So mathematically,  if [Salt] = [Acid]  then \frac{[Salt]}{[Acid]} = 1 .

And,  log (\frac{[Salt]}{[Acid]}) = 0

Therefore, equation (1) gives us the following.

         pH = pK_{a} (when acid and salt are equal in concentration)

Hence, pK_{a} of H_{2}CO_{3} (carbonic acid) is 6.35.

And, with this we have following results.

In (A) and (D) we have the case \frac{[NaHCO_{3}]}{[H_{2}CO_{3}]}[/tex] i.e. [Salt] = [Acid].

Hence, for the cases pH = pK_{a} = 6.35.

(B)    [NaHCO_{3}] = 0.045 M and,  [H_{2}CO_{3}] = 0.45 M

Hence,   pH = 6.35 + log([NaHCO_{3}][[H_{2}CO_{3}])

                     = 6.35 + log(\frac{0.045}{0.45})

                     = 6.35 + (-1)

                     = 5.35

Therefore, it means that this buffer will be most suitable buffer as it has pH on acidic side and addition of slight excess base will not affect much of its pH value.

(C)    [NaHCO_{3}] = 0.45 M [H_{2}CO_{3}]

                          = 0.045 M

So,       pH = 6.35 + log(\frac{[NaHCO_{3}]}{[H_{2}CO_{3}]})

                  = 6.35 + log(\frac{0.45}{0.045})

                  = 6.35 + (+1)

                 = 7.35

This means that pH on Basic side makes it no more acidic buffer.

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3 years ago
Explain why are hydrogen and oxygen considered as wheares water as a compound?
Elina [12.6K]
Hydrogen and oxygen are different elements.

when two or more elements combine, they form a compound

hence, two molecules of hydrogen and one molecule of oxygen combine to form water as a compound
3 0
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