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Gnesinka [82]
3 years ago
5

The properties of a given substance are governed by various forces or interactions. Consider the following 4 forces or interacti

ons: covalent bonding dispersion forces hydrogen bonding dipole-dipole interactions Which of the following correctly lists these four types of interactions/forces according to increasing strength (weakest to strongest)? hydrogen; dipole; covalent; dispersion
Chemistry
2 answers:
Ne4ueva [31]3 years ago
4 0

Answer:

weakest to strongest

  • dispersion forces
  • dipole-dipole interactions
  • hydrogen bonding
  • covalent bonding

Explanation:

Covalent bonding is an intramolecular interactions that hold the atoms together. Dispersion forces, hydrogen bonding and dipole-dipole interactions are intermolecular interactions . Intramolecular interactions are stronger than intermolecular interactions .

Dipole-dipole interactions occur when the partially positively charged part of a molecule interacts with the partially negatively charged part of the neighboring molecule. They are relative strong.

Hydrogen bonding is a special kind of dipole-dipole interaction that occurs specifically between a hydrogen atom bonded to either an oxygen, nitrogen, or fluorine atom. It is the strongest dipole-dipole interaction.

Dispersion forces  exist between all types of molecules, whether ionic or covalent (polar or nonpolar). They are the weakest of the intermolecular forces.

finlep [7]3 years ago
3 0
The strongest forces are those that have a really tight hold on molecules. Covalent bonds are extremely strong because those are direct connections. Hydrogen bonds are connections between molecules, and are weaker than covalent bonds. For your information, hydrogen bonds are a type of dipole-dipole interaction. The weakest forces are London Disperson Forces (all atoms and molecules have those with one another). If by dipole you mean ionic dipole, then the ANSWER: London Dispersion, Hydrogen, Covalent, Ionic-dipole
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Crazy boy [7]

Answer:

<u>5 moles S x (36.02 g S/mole S) = 180.1 grams of S</u>

Explanation:

The periodic table has mass units for every element that can be correlated with the number of atoms of that element.  The relationship is known as Avogadro's Number.  This number, 6.02x10^{23} , is nicknamed the mole, which scientists found to be a lot more catchy, and easier to write than  6.02x10^{23}.  <u>The mole is correlated to the atomic mass of that element.</u>  The atomic mass of sulfur, S, is 36.02 AMU, atomic mass units.  <u>But it can also be read as 36.02 grams/mole.</u>

<u></u>

<u>This means that 36.02 grams of S contains 1 mole (6.02x</u>10^{23}<u>) of S atoms</u>.

<u></u>

This relationship holds for all the elements.  Zinc, Zn, has an atomic mass of 65.38 AMU, so it has a "molar mass" of 65.38 grams/mole.  ^5.38 grams of Zn contains 1 mole of Zn atoms.  

And so on.

5.0 moles of Sulfur would therefore contain:

(5.0 moles S)*(36.02 grams/mole S) = <u>180.1 grams of S</u>

Note how the units cancel to leaves just grams.  The units are extremely helpful in mole calculations to insure the correct mathematical operation is done.  To find the number of moles in 70 g of S, for example, we would write:

(70g S)/(36.02 grams S/mole S) = 1.94 moles of S.  [<u>Note how the units cancel to leave just moles</u>]

4 0
2 years ago
Water's heat of fusion is 80. cal/g , its specific heat is 1.0calg⋅∘C, and its heat of vaporization is 540 cal/g . A canister is
Pani-rosa [81]
<span>294400 cal The heating of the water will have 3 phases 1. Melting of the ice, the temperature will remain constant at 0 degrees C 2. Heating of water to boiling, the temperature will rise 3. Boiling of water, temperature will remain constant at 100 degrees C So, let's see how many cal are needed for each phase. We start with 320 g of ice and 100 g of liquid, both at 0 degrees C. We can ignore the liquid and focus on the ice only. To convert from the solid to the liquid, we need to add the heat of fusion for each gram. So multiply the amount of ice we have by the heat of fusion. 80 cal/g * 320 g = 25600 cal Now we have 320 g of ice that's been melted into water and the 100 g of water we started with, resulting in 320 + 100 = 420 g of water at 0 degrees C. We need to heat that water to 100 degrees C 420 * 100 = 42000 cal Finally, we have 420 g of water at the boiling point. We now need to pump in an additional 540 cal/g to boil it all away. 420 g * 540 cal/g = 226800 cal So the total number of cal used is 25600 cal + 42000 cal + 226800 cal = 294400 cal</span>
6 0
3 years ago
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SOVA2 [1]
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5 0
3 years ago
Most of the energy released by nuclear fission is in the form of_________rays.
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3 0
3 years ago
A solid with a density of 3.57g/mL and mass of 19.5g is added to a graduated cylinder that contain 23.2mL of water. What is the
NNADVOKAT [17]

Answer:

Volume of liquid = 28.7 mL

Explanation:

Given data;

Density of solid = 3.57 g/ml

Mass of solid = 19.5 g

Volume of water = 23.2 mL

Total volume when solid is dropped into graduated cylinder= ?

Solution:

Density = mass/ volume

v = m/d

v = 19.5 g/ 3.57 g/ml

v = 5.5 mL

Volume of liquid = volume of water + volume of solid

Volume of liquid = 23.2 mL + 5.5 mL

Volume of liquid = 28.7 mL

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3 years ago
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