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ivann1987 [24]
3 years ago
9

(Chemistry question)

Chemistry
1 answer:
Anastaziya [24]3 years ago
6 0
So to answer this we will use the next procedure:
<span>First balance the equation:
2 C6H5OH + 15 O2 --> 12 CO2 + 6 H2O
Phenol (C6H5OH) reacts with O2 in a 2:15 ratio.
This means:
moles phenol 2 / moles O2 = 2 / 15
moles phenol = (2/15)*0.200 = 0.0267
Molar mass of phenol is 94 g/mol
Mass of phenol would = 0.0267*94 = 2.5 g
</span>I hope this can help
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The pyrolysis of ethane proceeds with an activation energy of about 300 kJ/mol. How much faster is the decomposition at 625°C th
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Answer:

The decomposition of ethane is 153.344 times much faster at 625°C than at 525°C.

Explanation:

According to the Arrhenius equation,

K=A\times e^{\frac{-Ea}{RT}}

\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_2 = rate of reaction at T_2

K_1 = rate of reaction at T_1

Ea = activation energy of the reaction

R = gas constant = 8.314 J/K mol

E_a=300 kJ/mol=300,000 J/mol

T_2=625^oC=898.15 K,T_1=525^oC=798.15 K

\log (\frac{K_2}{K_1})=\frac{300,000 J/mol}{2.303\times 8.314 J/K mol}[\frac{1}{798.15 K}-\frac{1}{898.15 K}]

\log (\frac{K_2}{K_1})=2.185666

K_2=153.344\times K_1

The decomposition of ethane is 153.344 times much faster at 625°C than at 525°C.

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3 years ago
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