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Hunter-Best [27]
3 years ago
12

A scientist eliminated all living organisms in a jar of soup by heating it. He then left the soup jar uncovered for some days. A

fter a few days, he saw molds in the soup. What most likely formed the mold?
Chemistry
2 answers:
velikii [3]3 years ago
6 0
Spores in the air or contamination through some sort of insect interaction. In an open system, there are billions of microbial agents floating around. With an open container containing a food source and time, the likelihood of contamination is nearly %100.
tigry1 [53]3 years ago
6 0

Answer:

Spores transported by the air.

Explanation:

Hello,

In biology, molds account for masses of mycelium, that is vegetative filaments or hyphaes and fruiting structures, produced by various fungi like Aspergillus, Penicillium, and Rhizopus. Such fungi, are associated with food spoilage and plant diseases, therefore, when they reproduce, they release spores which are spread to the air and subsequently transported to suitable sources of substrate allowing them to grow again. In such a way, since the jar was uncovered, spores transported by the air were allowed to get into the soup and grow there.

Best regards.

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4 years ago
Aluminum finds application as a foil for wrapping food stuves. Why?
pshichka [43]

Answer:

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Explanation:

8 0
1 year ago
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pantera1 [17]
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6 0
3 years ago
A 35.0-ml sample of 0.20 m lioh is titrated with 0.25 m hcl. What is the ph of the solution after 23.0 ml of hcl have been added
kiruha [24]
<h3><u>Answer;</u></h3>

pH = 12.33

<h3><u>Explanation;</u></h3>

The equation of reaction is :

LiOH(aq) + HCl(aq) --> LiCl(aq) + H2O(l)

Reactants left after the titrant is added;

Total Moles LiOH;

= 0.035L LiOH × (0.2moles/L)

= 0.007moles of LiOH

Moles of HCl;

= 0.023L HCl × (0.25moles/L)

= 0.00575moles HCl is the limiting reagent

Reacting amount of moles of LiOH;

= 0.0575 moles HCl *(1mole LiOH/1moles HCl)

=0.00575 moles LiOH (reacted)

Moles of LiOH left;

= 0.007moles total - 0.00575moles that react

= .00125 moles of LiOH (left)

LiOH is a strong base, which means that it ionizes completely.  

0.00125moles LiOH *(moles/0.058L) = 0.02155M of LiOH

LiOH(aq) --> Li+(aq) + OH-(aq)

[LiOH] = [OH-] = 0.02155 M

pOH = -log[OH-]

pOH = -log(0.02155)

pOH= 1.67

pH = 14 - pOH

pH = 14 - 1.67

pH = 12.33

7 0
3 years ago
When a redox reaction that takes place in an acidic solution involves an oxygen imbalance, oxygen should be balanced by adding _
olya-2409 [2.1K]

Balancing redox reactions:

Oxygen should be balanced by adding H_{2}O  as needed, while hydrogen should be balanced by adding H^{+}.

What is a redox reaction?

Redox reactions, also known as oxidation-reduction reactions, involve the simultaneous oxidation and reduction of two different reactants.

The Half-Equation Method is one technique used to balance redox processes. The equation is divided into two half-equations using this technique: one for oxidation and one for reduction.

By changing the coefficients and adding H_{2}O, H^{+}, and e^{-} in that order, each reaction is brought into equilibrium:

  1. By putting the right number of water (H_{2}O) molecules on the other side of the equation, the oxygen atoms are brought into balance.
  2. By adding H^{+} ions to the opposing side of the equation, one can balance the hydrogen atoms (including those added in step 2 to balance the oxygen atom).
  3. Total the fees for each side. Add enough electrons (e^{-}) to the more positive side to make them equal. (As a general rule, e^{-} and  H^{+}are nearly always on the same side.)
  4. The e^{-} on either side must be made equal; if not, they must be multiplied by the lowest common multiple (LCM) in order to make them equal.
  5. One balanced equation is created by adding the two half-equations and canceling out the electrons. Additionally, common terms should be eliminated.
  6. Now that the equation has been verified, it can be balanced.

Learn more about redox reaction here,

brainly.com/question/20068208

#SPJ4

7 0
2 years ago
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