A chromate ion consist of four oxygen atom bonded to be a chromium atom. It has two extra electrons. the formula for this

What do element; atoms; molecule; chemical bond; compound; mixture; and substance have in common

sleet_krkn [62]

They are all things you can do to elements on the periodic table?

7 0

3 years ago

Brownian motion is

ioda

Answer: A.

Explanation:

Brownian motion is the random motion of a particle as a result of collisions with surrounding gaseous molecules. Diffusiophoresis is the movement of a group of particles induced by a concentration gradient. This movement always flows from areas of high concentration to areas of low concentration.

Example: The movement of pollen grains on still water. Motion of dust motes in a room (though largely influenced by air currents).

6 0

3 years ago

How many mols of a 3M NaOH solution are in 1L of the solution?

Alex

To calculate this, we need the Molarity formula. This formula tell us that Molarity, which is a concentration unit, is equal to the number of moles divided by the volume. In this question we already have the Molarity and the Volume, so let's build our equation:

C = n/V (You can see Molarity with the letter "C" because it means concentration)

3 = n/1

n = 1 * 3

n = 3 moles of NaOH

6 0

1 year ago

You must answer all questions to get credit for this assignment. Use the notes above and/or the textbook to help you find the an

Allisa [31]

Explanation:

(1). It is known that in a reaction equation, reactants are placed or written on left hand side and products are written on the right hand side.

For example, $N_{2} + 3H_{2} \rightarrow 2NH_{3}$

Hence, in a reaction equation you start with the reactants and end up with the products.

(2). The number of atoms in a reaction will remain the same because according to the law of conservation of mass, mass of reactants will be equal to the mass of products.

Therefore, number of atoms on the reactant side will be equal to the number of atoms on product side.

7 0

3 years ago

Dissolution of KOH, ΔHsoln:

swat32

Using Hess's law we found:

1) By adding reaction 10.2 with the reverse of reaction 10.1 we get reaction 10.3:

KOH(aq) + HCl(aq) → H₂O(l) + KCl(aq) ΔH (10.3)

2) The ΔHsoln must be subtracted from ΔHneut to get the total change in enthalpy (ΔH).

The reactions of dissolution (10.1) and neutralization (10.2) are:

KOH(s) → KOH(aq) ΔHsoln (10.1)

KOH(s) + HCl(aq) → H₂O(l) + KCl(aq) ΔHneut (10.2)

1) According to Hess's law, the total change in enthalpy of a reaction resulting from differents changes in various reactions can be calculated as the sum of all the enthalpies of all those reactions.

Hence, to get reaction 10.3:

KOH(aq) + HCl(aq) → H₂O(l) + KCl(aq) (10.3)

We need to add reaction 10.2 to the reverse of reaction 10.1

KOH(s) + HCl(aq) + KOH(aq) → H₂O(l) + KCl(aq) + KOH(s)

Canceling the KOH(s) from both sides, we get reaction 10.3:

KOH(aq) + HCl(aq) → H₂O(l) + KCl(aq) (10.3)

2) The change in enthalpy for reaction 10.3 can be calculated as the sum of the enthalpies ΔHsoln and ΔHneut:

$\Delta H = \Delta H_{soln} + \Delta H_{neut}$