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uranmaximum [27]

2 years ago

11

he atomic number of fluorine is 9. How many electrons does an ion of fluorine have if it is represented by the symbol shown belo

w? 19F1- A. 8 electrons B. 9 electrons C. 10 electrons D. 20 electrons

2 answers:

Olegator [25]2 years ago

6 0

Answer:

it is D.

Explanation:

because im always right, and i also put C like the other guy said but it was wrong.. its D.

Stells [14]2 years ago

4 0

The atomic number of fluorine is 9.

Atomic number is the number of protons present in the element. The number of electrons and protons is same in a neutral element.

The given ion of fluorine is $^{19}F^{-}$ . It represents a uninegative anion with a mass number of 19.

It is an anion with a charge of -1, this means that there is an additional electron in the ion. The number of electrons in this ion are 9 + 1 = 10 electrons

The correct answer will be C. 10 electrons

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Answer:

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Explanation:

Given that

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As we know that relationship between diameter and yield strength

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$\sigma_y\ =Yield\ strength$

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So now by putting the values

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$163=\sigma_o+\dfrac{K}{\sqrt 35}$ ------------1

d= 17 μm ,yield strength = 192 MPa

$192=\sigma_o+\dfrac{K}{\sqrt 17}$ ------------2

From equation 1 and 2

$192-163=\dfrac{K}{\sqrt 17}-\dfrac{K}{\sqrt 35}$

K=394.53

By putting the values of K in equation 1

$163=\sigma_o+\dfrac{394.53}{\sqrt 35}$

$\sigma_o\ =96.31\ MPa$

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Now when d= 12 μm

$\sigma_y=96.31+\dfrac{394.53}{\sqrt 12}$

$\sigma_y\ =210.2\ MPa$

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xeze [42]

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Explanation:

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