The scientist that invented a model that shows the electron cloud is Neil Bohr. <span />
Bohr's theory states that the motion of the electron (particle) around the nucleus is very much similar to motion of the planets around the sun in the solar system. Both in the mathematical and physical sense.
The Bohr's Atomic theory only explains the motion of the electrons in discrete atomic orbitals that are predicted by the Bohr's equation.
It strictly implies that the electron only exists in these discreet orbitals and fails to explain anything about the nature of the electron in between the discrete orbitals.
The modern atomic theory does not share this limitation as it does not impose the electron to only occupy the discrete orbitals and neither does it impose particle nature upon the electron.
In the modern theory does not focus on describing the motion of the electron around the orbital but rather the probability of finding an electron around the nucleus. The modern atomic orbitals or electron clouds are the regions in which the probability of finding the electron is the highest when the wave function collapses. The Schrödinger's wave equation explains the evolution of the wave function in time. Hence enabling us to predict the future possible locations of the electron but never the exact location as that is impossible due to the Heisenberg's Uncertainty principle.
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K₂SO₄ + CaI₂ → CaSO₄ + KI
K: 2 K: 1
S: 1 S: 1
O: 4 O: 4
Ca: 1 Ca: 1
I: 2 I: 1
↓
K₂SO₄ + CaI₂ → CaSO₄ + 2KI
K: 2 K: 2
S: 1 S: 1
O: 4 O: 4
Ca: 1 Ca: 1
I: 2 I: 2
Taking into account the definition of avogadro's number, 3.82×10⁻³ moles of H are 2.3×10²¹ particles of H.
<h3>
Avogadro's Number</h3>
Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.
<h3>This case</h3>
Then you can apply the following rule of three: if 6.023×10²³ particles are contained in 1 mole of H, then 2.3×10²¹ particles are contained in how many moles of H?
amount of moles of H= (2.3×10²¹ particles × 1 mole)÷ 6.023×10²³ particles
<u><em>amount of moles of H= 3.82×10⁻³ moles</em></u>
Finally, 3.82×10⁻³ moles of H are 2.3×10²¹ particles of H.
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These organs belong to the nervous system
