5. How many miles are there in 3.44 x 10^8 inches?

What is the compound SCI2

lys-0071 [83]

Answer:

It is called Sulfur dichloride

3 0

3 years ago

Helpppppppppp pleaseeeeeee

zhannawk [14.2K]

I would like to help if tell me what grade this is.

6 0

2 years ago

What's the pH of a solution composed of 0.2 moles of NH3 and 0.15 moles of nh4cl

Norma-Jean [14]

Answer:

$pH=4.63$

Explanation:

Hello!

In this case, since the ionization of ammonia, which is a weak base, is written as:

$NH_3+H_2O\rightleftharpoons NH_4^++OH^-$

We can see that the ammonium ion is the conjugate acid whereas the hydroxide ions the conjugate base; that is why we use the Henderson-Hasselbach equation to compute the pH, given the pKb of ammonia 4.75:

$pH=pKb+log(\frac{[conj\ acid]}{[base]} )$

In such a way, for the given moles of ammonia, base, and those of ammonium chloride, conjugate acid form, we obtain:

$pH=4.75+log(\frac{0.15}{0.2} )\\\\pH=4.63$

Best regards!

8 0

3 years ago

What is the formula for an ionic compound made of barium and nitrogen? (a)- BaN (b)- Ba3N2 (c)- Ba2N4 (d)- Ba2N3 (e) None of the

Andrej [43]

Answer:

kuyfyi

Explanation:

7 0

3 years ago

A 33.153 mg sample of a chemical known to contain only carbon, hydrogen, sulfur, and oxygen is put into a combustion analysis ap

elena-14-01-66 [18.8K]

Answer:

The empirical formula of the compound = $C_4H_8S_1O_1$

Explanation:

Mass of carbon dioxide gas = 59.060 mg = 0.059060 g

1 mg = 0.001 g

Moles of carbon dioxide = $\frac{0.059060 g}{44 g/mol}=0.0013 mol$

Moles of carbon in 0.0013 moles of carbon dioxide gas = 1 × 0.0013 mol = 0.0013 mol

Mass of 0.0013 moles of carbon = $12 g/mol\times 0.0013 mol=0.0156 g$

Mass of water = 24.176 mg = 0.024176

Moles of water = $\frac{0.024176 g}{18 g/mol}=0.0013 mol$

Moles of hydrogen in 0.0013 moles of water = 2 × 0.0013 mol = 0.0026 mol

Mass of 0.0013 moles of hydrogen= $1 g/mol\times 0.0013 mol=0.0013 g$

Mass of sulfur dioxide = 20.326 mg = 0.020326 g

Moles of sulfur dioxide = $\frac{0.020326 g}{64 g/mol}=0.00032 mol$

Moles of sulfur in 0.00032 moles of sulfur dioxide = 1 × 0.00032 mol = 0.00032 mol

Mass of 0.00032 moles of sulfur = $32 g/mol\times 0.00032 mol=0.01024 g$

Mass of oxygen in the sample = x

Mass of sample = 33.153 mg = 0.033153 g

0.033153 g = 0.0156 g + 0.0013 g + 0.01024 g + x

x = 0.006013 g

Moles of oxygen = $\frac{0.006013 g}{16 g/mol}=0.00038 mol$

For empirical formula divide the lowest number of moles of elemnt from all the moles of the all the elements:

Carbon : $\frac{0.0013 mol}{0.00032 mol}=4$

Hydrogen: $\frac{0.0026 mol}{0.00032 mol}=8$

Sulfur : $\frac{0.00032 mol}{0.00032 mol}=1$

Oxygen : $\frac{0.00038 mol}{0.00032 mol}=1$

The empirical formula of the compound = $C_4H_8S_1O_1$

8 0

4 years ago