1 gram of sugar because super molecules are bigger then the ions of dissolved salt
Answer:
a. Amadeo Avogadro (1776-1856) was the author of Avogadro's Hypothesis in 1811, which, together with Gay-Lussac's Law of Combining Volumes, was used by Stanislao Cannizzaro to elegantly remove all doubt about the establishment of the atomic weight scale at the Karlsruhe Conference of 1860. The name "Avogadro's Number" is just an honorary name attached to the calculated value of the number of atoms, molecules, etc. in a gram mole of any chemical substance. Of course if we used some other mass unit for the mole such as "pound mole", the "number" would be different than 6.022 x 1023.
b. The first person to have calculated the number of molecules in any mass of substance was Josef Loschmidt, (1821-1895), an Austrian high school teacher, who in 1865, using the new Kinetic Molecular Theory (KMT) calculated the number of molecules in one cubic centimeter of gaseous substance under ordinary conditions of temperature of pressure, to be somewhere around 2.6 x 1019 molecules. This is usually known as "Loschmidt's Constant.
Task 2
a.
Percent composition is the percent by mass of each element present in a compound. Water, H2O, is the first example. One mole of water is 18.0152 grams. In that compound, there are two moles of H atoms and 2 x 1.008 = 2.016 grams. That's how many grams of hydrogen are present in one mole of water. this is an example. i don't know what you are describing though. i need more info for this question
b. 6.022 to 6.023 x 10^23
c. i don't know what this one is since there is nothing to describe the unknown liquid.
d. Yes a killer, but not a specific person
Explanation:
d G = 2 (dG NOCl) - 2 (dG NO)
= 2 * 66.08 - 2 * 87.6 = -43.04 kJ /mol
dG = - 2.303 RT log K
-43.04 = - 2.303 RT log K
7.54 = log K
K = 3.42 * 10^7
Kp = k (RT)^dn
d n = 2 - 1 -2 = -1
Kp = (3.42 * 10^7) (8.314 * 298)^-1
Kp = 1.31 * 10^4
Answer:
V₂ = 495.89 mL
Explanation:
Given data:
Initial number of moles = 0.213 mol
Initial volume = 652 mL
Final number of moles = 0.162 mol
Final volume = ?
Solution:
V₁/n₁ = V₂/n₂
By putting values,
652 mL/0.213 mol = V₂ /0.162 mol
V₂ = 652 mL 0.162 mol /0.213 mol
V₂ = 105.62 mL.mol /0.213 mol
V₂ = 495.89 mL
