Question

Evaluate this indefinite integral (world)joy^world-1d(joy)

Answer 1

Answer:

The answer is $joy^{world} + C$

Step-by-step explanation:

Given the indefinite integral $\int (world)joy^{world-1}d(joy)$

Let world → a

         joy → x

Therefore, the integral becomes $\int ax^{a-1}dx$

                                                    = $a\frac{x^{a-1+1} }{a-1+1} + C$

                                                    = $x^{a} + C$

Replacing, a → world

                  x → joy  

Hence, $\int (world)joy^{world-1}d(joy)$ = $joy^{world} + C$

Answer 2

Let be y= world, and joy=x
so we have integral (world)joy^world-1d(joy) = integ(yx^y-1)dx, y is a constant independant of x, so integ(yx^y-1)dx = y . integ(x^y-1)dx
=y .(x^y-1+1 / y-1 +1) + C=(x^y) + C

the answer is joy^world