Answer:
Explanation:
Gravity on the surface of planet is given as
as we know that
now gravity on the planet is
so we have
now we know that
so we will say
The trickiest part of this problem was making sure where the Yakima Valley is.
OK so it's generally around the city of the same name in Washington State.
Just for a place to work with, I picked the Yakima Valley Junior College, at the
corner of W Nob Hill Blvd and S16th Ave in Yakima. The latitude in the middle
of that intersection is 46.585° North. <u>That's</u> the number we need.
Here's how I would do it:
-- The altitude of the due-south point on the celestial equator is always
(90° - latitude), no matter what the date or time of day.
-- The highest above the celestial equator that the ecliptic ever gets
is about 23.5°.
-- The mean inclination of the moon's orbit to the ecliptic is 5.14°, so
that's the highest above the ecliptic that the moon can ever appear
in the sky.
This sets the limit of the highest in the sky that the moon can ever appear.
90° - 46.585° + 23.5° + 5.14° = 72.1° above the horizon .
That doesn't happen regularly. It would depend on everything coming
together at the same time ... the moon happens to be at the point in its
orbit that's 5.14° above ==> (the point on the ecliptic that's 23.5° above
the celestial equator).
Depending on the time of year, that can be any time of the day or night.
The most striking combination is at midnight, within a day or two of the
Winter solstice, when the moon happens to be full.
In general, the Full Moon closest to the Winter solstice is going to be
the moon highest in the sky. Then it's going to be somewhere near
67° above the horizon at midnight.
On foot= 1 kilometer per 5 minutes
Bike= I kilometer per 2 minutes
3 minutes fast per mile on bike
Answer:
v = 2 cm/s
Explanation:
The equation of the wave is
y(x,t) = (2.0cm)*cos(2π*x−4π*t)
Where,
x is measured in cm
t in s
A more general formula for this equation would be
y(x,t) = A*cos(k*x−ω*t)
Where,
A = amplitude.
k = the wavenumber
ω = the angular frequency
The velocity of the wave corresponds to
v = ω/k
v = 4π / 2π = 2 cm/s
v = 2 cm/s
Moon orbits earth. it's viewable somewhere in the world every 28 days. if the place where it's viewed were by the sea, then the tidal patterns of water - high tide and low tide - could be correlated to the moon being seen or otherwise. If the moon is is visible, it presumably gives one gravitational pull on the water. If the moon is not visible, then it presumably gives a less gravitational pull. Maybe "spring" suggests a high high tide (as in growth ?) and "neap" suggests a low high tide ???
