Answer:
The tension in the rope is 49.66 N.
Explanation:
Given that,
Mass of bucket m= 23.0 kg
Diameter = 0.300 m
Mass of rope M= 13.0 kg
Height = 10.5 m
Suppose we need to find the tension in the rope while the bucket is falling.
We need to calculate the acceleration
Using balance equation
..(I)
We need to calculate the tension in the rope
Using formula of tension
....(II)
Put the value of T in the equation (I)
Put the value into the formula
Now, put the value of a in equation (II)
Hence, The tension in the rope is 49.66 N.
Answer:
The balls velocity is 1 divided by 3
Answer:
Explanation:
v = u +at
u = 0
a = 2.3 m /s²
t = 20 s
v = 2.3 x 20
= 46 m /s
Distance covered under acceleration of 2.3 m/s²
s = ut + 1/2 at²
= 0 + .5 x 2.3 x 20²
= 460 m
After that it moves under free fall ie g acts on it downwards .
v² = u² - 2gh , h is height moved by it under free fall
0 = 46² - 2 x 9.8 h
h = 107.96 m
Total height attained
= 460 + 107.96
= 567.96 m
b ) At its highest point ,it stops so its velocity = 0
c ) rocket's acceleration at its highest point = g = 9.8 downwards .
At highest point , it is undergoing free fall so its acceleration = g