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3 years ago

Drag the tiles to the correct boxes to complete the pairs.

Chemistry

1 answer:

Amiraneli [1.4K]3 years ago

6 0

<u>Explanation:</u>

Phosphorus and oxygen atoms are considered as non-metals and two non-metals usually form covalent bonds.

A covalent bond is formed when sharing of electrons takes place between the atoms forming a bond.

The nomenclature of a covalent compound is given by:

The less electronegative element is written first.
The more electronegative element is written then, and a suffix is added with it. The suffix added is '-ide'.
If atoms of an element is greater than 1, then prefixes are added which are 'mono' for 1 atom, 'di' for 2 atoms, 'tri' for 3 atoms and so on..

From the two atoms, less electronegative atom is phosphorus and thus, is written first.

Naming of the given compound are as follows:

1. $P_4O_7$ = The name given to this compound is tetraphosphorus heptoxide

2. $P_2O_5$ = The name given to this compound is diphosphorus pentoxide

3. $P_2O_4$ = The name given to this compound is diphosphorus tetroxide

4. $PO$ = The name given to this compound is phosphorus monoxide

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The half-life of cesium-137 is 30 years. Suppose we have a 180 mg sample. Find the mass that remains after t years. Let y(t) be

Stels [109]

Explanation:

1) Initial mass of the Cesium-137= $N_o$ = 180 mg

Mass of Cesium after time t = N

Formula used :

$N=N_o\times e^{-\lambda t}\\\\\lambda =\frac{0.693}{t_{\frac{1}{2}}}$

Half life of the cesium-137 = $t_{1/2}=30 years[p/tex]where,
[tex]N_o$ = initial mass of isotope

N = mass of the parent isotope left after the time, (t)

$t_{\frac{1}{2}}$ = half life of the isotope

$\lambda$ = rate constant

$N=N_o\times e^{-(\frac{0.693}{t_{1/2}})\times t}$

Now put all the given values in this formula, we get

$N=180mg\times e^{-\frac{0.693}{30 years}\times t}$

Mass that remains after t years.

$N=180 mg\times e^{0.0231 year^{-1}\times t}$

Therefore, the parent isotope remain after one half life will be, 100 grams.

t = 70 years

$N_o=180 mg$

$t_{1/2}= 30 yeras$

$N=180mg\times e^{-\frac{0.693}{30 years}\times 70 years}$

N = 35.73 mg

35.73 mg of cesium-137 will remain after 70 years.

$N_o=180 mg$

$t_{1/2}= 30 yeras$

N = 1 mg

t = ?

$1 mg =180mg\times e^{-\frac{0.693}{30 years}\times t}$

$\frac{-30 year}{0.693}\times \ln \frac{1 mg}{180 mg}=t$

t = 224.80 years ≈ 225 years

After 225 years only 1 mg of cesium-137 will remain.

7 0

4 years ago

In neutron moderation, neutrons are slowed down so that:

erastovalidia [21]

B. Nuclear fission reactions are slowed down as well.

Neutron moderation is a substance which slows down neutron. In some reaction moderator is same as coolant.

This is also used to slow down nuclear fission reaction and continue chain reactions.

The collision between neutron and nuclei is more elastic and more neutrons will be slowed due to size of the neutron.

Learn more at brainly.com/question/24371385

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3 years ago

What element is being oxidized<br><br> Fe2O3 + 3CO -> 2FE +3C02

Vinvika [58]

Fe because oxidation mean loss of oxygen and Fe lose the oxygen so Fe is oxidised

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3 years ago

What is the name of the pores, or holes, on the outer layer of the sponge that take water in?

ivanzaharov [21]

The tiny holes in a sponges outer layer that take in water are called ostia, I believe. Hope it helps

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4 years ago

describe the trends in the atomic size, location energy and electrongavity from left to right across a period in periodic table

Elenna [48]

Atomic size decreases in a period but the ionization energy and electronegativity increases across a period.

<h3>Describe the trends in the atomic size, ionization energy and electronegativity?</h3>

Atomic radius decreases across a period because of nuclear charge increases whereas atomic radius of atoms generally increases from top to bottom within a group because there is again an increase in the positive nuclear charge.

Ionization energy increases when we move from left to right across an period and decreases from top to bottom.

Electronegativity also increases from left to right across a period and decreases from top to bottom.

So we can conclude that atomic size decreases in a period but the ionization energy and electronegativity increases across a period.

Learn more about Electronegativity here: brainly.com/question/24977425

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2 years ago