C. Your feet push down on the ground, and the ground pushes up on your feet.
<span>A plane flies along a straight line path after taking off, and it ends up 210 km farther east and 90.0 km farther north, relative to where it started. we should use Pythagoras theorem for this.
distance^2= 210^2 + 90^2.=228.47km, when rounding off this would comes around 230 km</span>
We're given the velocity at two points, and the time between the mentioned two points.
What we'll be calculating is the average acceleration (not to be confused with instantaneous acceleration).
Given two points, lets call them initial and final, the average acceleration is calculated as:
In which
is the final velocity (in your problem equal to 1m/s),
is the initial velocity (in your problem equal to 16 m/s), and
the time between two points (in your problem equal to 2s).
So, we plug-in our known values:
The answer is -7.5m/s^2.