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3 years ago

Calculate the velocity of a wave that has a frequency of 60 Hz and wavelength of 2.0 m/s

Physics

1 answer:

mote1985 [20]3 years ago

3 0

Answer:We have , a relation in frequency f and wavelength λ of a wave having the velocity v as ,

v=fλ ,

given f=60Hz , λ=20m ,

therefore velocity of wave , v=60×20=1200m/s

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How much work is done to move a 10,000-N car 20 meters?

Helga [31]

f = 10000N
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4 years ago

What kind of geologic feature do all earthquakes occur?

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Coastal areas near water bodies like sea and oceans

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3 years ago

A mass hangs on the end of a massless rope. The pendulum is held horizontal and released from rest. When the mass reaches the bo

drek231 [11]

Answer:

$T = 37.5 N$

Explanation:

As the pendulum reached to the lowest position then we will have

$T - mg = \frac{mv^2}{L}$

$14.2 - m(9.81) = \frac{m(2.9^2)}{L}$

now when it will reach to the height of the peg then its speed is given as

$v_f^2 - v_i^2 = 2 a d$

so we will have

$v_f^2 - 2.9^2 = 2(-9.81)(\frac{L}{5})$

$v_f^2 = 2.9^2 - 3.924L$

also we know that

$2.9^2 - 0 = 2(9.81)(L)$

$L = 0.43 m$

$m = 0.48 kg$

now we have speed of the pendulum when it reach the same height is given as

$v_f^2 = 2.9^2 - (3.924(0.43)$

$v_f = 2.6 m/s$

Now the tension in the string is given as

$T = \frac{mv_f^2}{\frac{L}{5}}$

$T = \frac{0.48(2.6)^2}{\frac{0.43}{5}}$

$T = 37.5 N$

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3 years ago

In general, the-------- the string or air column of a musical instrument is, the more harmonics are generated. shorter or longer

yanalaym [24]

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4 years ago

Read 2 more answers

Light rays from stars bend toward smaller angles as they enter Earth's atmosphere. a. Explain why this happens using Snell's law

Grace [21]

Answer:

Following are the answer to this question:

Explanation:

In option (a):

The principle of Snells informs us that as light travels from the less dense medium to a denser layer, like water to air or a thinner layer of the air to the thicker ones, it bent to usual — an abstract feature that would be on the surface of all objects. Mostly, on the contrary, glow shifts from a denser with a less dense medium. This angle between both the usual and the light conditions rays is referred to as the refractive angle.
Throughout in scenario, the light from its stars in the upper orbit, the surface area of both the Earth tends to increase because as light flows from the outer atmosphere towards the Earth, it defined above, to a lesser angle.

In option (b):

Rays of light, that go directly down wouldn't bend, whilst also sun source which joins the upper orbit was reflected light from either a thicker distance and flex to the usual, following roughly the direction of the curve of the earth.
Throughout the zenith specific position earlier in this thread, astronomical bodies appear throughout the right position while those close to a horizon seem to have been brightest than any of those close to the sky, and please find the attachment of the diagram.

8 0

3 years ago