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Gelneren [198K]
3 years ago
6

Calculate the velocity of a wave that has a frequency of 60 Hz and wavelength of 2.0 m/s

Physics
1 answer:
mote1985 [20]3 years ago
3 0

Answer:We have , a relation in frequency f and wavelength  λ of a wave having the velocity v as ,

           v=fλ ,

given f=60Hz , λ=20m ,

therefore velocity of wave , v=60×20=1200m/s

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Pls help me with this question
Arisa [49]

Answer:

dam 15 marks for that question that's ez marks there

4 0
2 years ago
What type of charge will an object have if the object contains less protons than electrons?
Burka [1]

Answer:

Hello, I believe it would have a negative charge considering protons have a positive charge while elctrons have a negative charge

Explanation:

6 0
3 years ago
For the potential , determine the number of bound states?A)6 b)4 c) 3 d) 1
s2008m [1.1K]

Do you see that blank, open space after the word "potential ..." ?

There's supposed to be a number there that actually tells us the value of the potential.  Without that number ... and a lot more description of the whole scenario here ... there's no possible answer to the question.

7 0
3 years ago
An electron experiences a magnetic force with a magnitude of 4.90×10−15 n when moving at an angle of 60.0 ∘ with respect to a ma
Leya [2.2K]
Missing questions: "find the speed of the electron".

Solution:
the magnetic force experienced by a charged particle in a magnetic field is given by
F=qvB \sin \theta
where
q is the particle charge
v its velocity
B the magnitude of the magnetic field
\theta the angle between the directions of v and B.

Re-arranging the formula, we find:
v= \frac{F}{qB \sin \theta}
and by substituting the data of the problem (the charge of the electron is q=1.6 \cdot 10^{-19} C), we find the velocity of the electron:
v= \frac{F}{qB \sin \theta}= \frac{4.90 \cdot 10^{-15}N}{(1.6 \cdot 10^{-19}C)(3.70 \cdot 10^{-3} T)(\sin 60^{\circ})}=9.56 \cdot 10^6 m/s
4 0
3 years ago
Compute the power output (watts) during one minute of treadmill exercise, given the following: Treadmill grade-10% Horizontal sp
erma4kov [3.2K]

Answer:

c. 981 watts

P=981\ W

Explanation:

Given:

  • horizontal speed of treadmill, v=100\ m.min^{-1}=\frac{5}{3} \ m.s^{-1}
  • weight carried, w=588.6\ N
  • grade of the treadmill, G\%=10\%

<u>Now the power can be given by:</u>

P=v.w

P=588.6\times\frac{5}{3} (where grade is the rise of the front edge per 100 m of the horizontal length)

P=981\ W

6 0
3 years ago
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