Answer
Chemical formula or Chemical Abstracts Service
Explanation:
A CAS (Chemical Abstracts Service) Registry Number is a unique identifier that tells you, for example, that acetone and dimethyl ketone are actually the same substance.
The simplest way to use the periodic table to identify<span> an </span>element<span> is by looking for the </span>element's<span> name or elemental symbol. The periodic table can be used to </span>identify <span>an </span>element<span> by looking for the </span>element's<span> atomic </span>number<span>. The atomic </span>number of<span> an </span>element<span> is the </span>number of<span> protons found within the atoms of that </span>element<span>.</span>
The empirical formula for the caproic acid, given the combustion analysis data is C₃H₆O
We'll begin bey obtaining the mass of carbon, hydrogen and oxygen in the compound. This is illustrated below:
How to determine the mass of C
- Mass of CO₂ = 9.78 g
- Molar mass of CO₂ = 44 g/mol
- Molar of C = 12 g/mol
- Mass of C =?
Mass of C = (12 / 44) × 9.78
Mass of C = 2.67 g
How to determine the mass of H
- Mass of H₂O = 20.99 g
- Molar mass of H₂O = 18 g/mol
- Molar of H = 2 × 1 = 2 g/mol
- Mass of H =?
Mass of H = (2 / 18) × 4
Mass of H = 0.44 g
How to determine the mass of O
- Mass of compound = 4.30 g
- Mass of C = 2.67 g
- Mass of H = 0.44 g
- Mass of O =?
Mass of O = (mass of compound) – (mass of C + mass of H)
Mass of O = 4.30 – (2.67 + 0.44)
Mass of O = 1.19 g
<h3>How to determine the empirical formula </h3>
The empirical formula of the compound can be obtained as follow:
- C = 2.67 g
- H = 0.44 g
- O = 1.19 g
- Empirical formula =?
Divide by their molar mass
C = 2.67 / 12 = 0.2225
H = 0.44 / 1 = 0.44
O = 1.19 / 16 = 0.074
Divide by the smallest
C = 0.2225 / 0.074 = 3
H = 0.44 / 0.0744 = 6
O = 0.074 / 0.074 = 1
Thus, the empirical formula of the compound is C₃H₆O
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Answer:
I can provide a proper answer since there are no bonds specified.
Explanation:
Protons, Electrons, and Neutrons are all parts of atoms, the electrons are on the outside rings of the atom, with the neutrons and electrons on the inside of the atom. The electrons are negatively charged, while the protons are positively charged and the neutrons no charge/neutral. Let me know if you would like to learn more!
