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kakasveta [241]
3 years ago
6

Can someone help me, please?

Chemistry
1 answer:
Korolek [52]3 years ago
6 0
6.B. NADPH and 8.B. ETHYNE
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How Could Spectroscopy Be Used to Distinguish Between the Following
skelet666 [1.2K]

Spectroscopy be used to distinguish between the following is the compound B has a peak at 3200 – 3500 cm⁻¹ in its IR spectrum.

<h3>What is spectroscopy?</h3>

Spectroscopy is the study of emission or absorption of light. It is used to study the structure of atoms and molecules.

The three types of spectroscopy are:

  • atomic absorption spectroscopy (AAS)
  • atomic emission spectroscopy (AES)
  • atomic fluorescence spectroscopy (AFS)

Thus, the correct option is B, the compound B has a peak at 3200 – 3500 cm⁻¹ in its IR spectrum.

Learn more about spectroscopy

brainly.com/question/5402430

#SPJ1

5 0
3 years ago
Nguyên tử X có tổng số hạt là 34, số khối X là 56. Điện tích hạt nhân của X là?
Verizon [17]

Answer:

can u tell the question in english

8 0
2 years ago
Three isotopes of argon occur in nature – 36 18Ar, 38 18Ar, 40 18Ar. Calculate the average atomic mass of argon to two decimal p
likoan [24]

Answer: 3) 39.96 amu

Explanation:

Mass of isotope Ar- 36 = 35.97 amu

% abundance of isotope Ar- 36= 0.337% = \frac{0.337}{100}=3.37\times 10^{-3}

Mass of isotope Ar- 38 = 37.96 amu

% abundance of isotope 2 = 0.063 % = \frac{0.063}{100}=6.3\times 10^{-4}

Mass of isotope Ar- 40 = 39.96 amu

% abundance of isotope 2 = 99.600 % = \frac{99.600}{100}=0.996

Formula used for average atomic mass of an element :

\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})

A=\sum[(35.97\times 3.37\times 10^{-3})+(37.96\times 6.3\times 10^{-4})+(39.96\times 0.996)]

A=39.96amu

Therefore, the average atomic mass of argon is 39.96 amu

4 0
4 years ago
two people start out 100 meters apart from each other and start moving towards each other at the same time. One person is moving
andreev551 [17]

Answer:

1.332 meters per second. // 2.664 meters per second.

Explanation:

the slower person moved 33.3 meters, and the faster person moved 66.6 meters.

the slower person is moving 33.3 meters in 25 seconds, while the other person is moving 66.6 meters in 25 seconds

slower person moved 33.3/25 = 1.332 meters per second.

faster person moved 66.6/25 = 2.664 meters per second.

4 0
3 years ago
40 g of CaCO3 is how many moles of CaCO3?<br> 10 moles<br> 0.4 moles<br> 40 moles<br> 100 moles
AleksandrR [38]

Answer:

0.4 moles

Explanation:

To convert between moles and grams you need the molar mass of the compound. The molar mass of of CaCO3 is 100.09g/mol. You use that as the unit converter.

40gCaCO3* 1mol CaCO3/100.09gCaCO3 = 0.399640 mol CaCO3

This rounds to 0.4 moles CaCO3

8 0
3 years ago
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