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3 years ago

Forces come in pairs. What are these pairs called?

Physics

2 answers:

LiRa [457]3 years ago

7 0

Answer:

"action-reaction force pairs"

Explanation:

...

dlinn [17]3 years ago

6 0

Answer: Action-Reaction force pairs

Explanation: please make me brainiest thanks

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An alpha particle can be produced in certain radioactive decays of nuclei and consists of two protons and two neutrons. The part

Varvara68 [4.7K]

Answer:

Explanation:

charge, q = 2e = 2 x 1.6 x 10^-19 C = 3.2 x 10^-19 C

mass, m = 4 u = 4 x 1.661 x 10^-27 kg = 6.644 x 10^-27 kg

Radius, r = 4.5 cm = 0.045 m

Magnetic field, B = 1.20 T

(a) Let the speed is v.

$v=\frac{Bqr}{m}$

$v=\frac{1.20\times 3.2\times 10^{-19}\times 0.045}{6.644\times 10^{-27}}$

v = 2.6 x 10^6 m/s

(b) Let T be the period of revolution

$T=\frac{2\pi r}{v}$

$T=\frac{2\times 3.14\times 0.045}{2.6\times 10^{6}}$

T = 1.09 x 10^-7 s

$K=\frac{B^{2}\times q^{2}\times r^{2}}{2m}$

$K=\frac{\left ( 1.20\times 3.2 \times 10^{-19}\times 0.045 \right )^{2}}{2\times 6.644\times 10^{-27}}$

K = 2.25 x 10^-14 J

(d) Let the potential difference is V.

K = qV

$V = \frac{K}{q}$

$V= \frac{2.25\times 10^-14}{3.2\times 10^{-19}}$

V = 70312.5 V

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3 years ago

What is Newton's second law of motion?

Lesechka [4]

What is Newton's second law of motion?

Newton's second law of motion states that the rate of change of momentum is directly proportional to the applied force and the direction of change of momentum takes place towards direction of applied force.

<h3> $\bullet$ What do you come to know from Newton's second law of motion?</h3>

1. Concept of Momentum.

2. Measurement of Force.

_____________________________________

<h3 /><h3 /><h3 /><h3> $\bf Hope \: it \: helps \: you$ .</h3>

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3 years ago

Read 2 more answers

The flywheel of a steam engine begins to rotate from rest with a constant angular acceleration of 1.33 rad/s2. It accelerates fo

Svetradugi [14.3K]

Answer:

We first to know that if the wheel rotates from rest means that at t=0 the velocity and the angle rotated is 0.

Then, we know:

$\alpha = 1.33 = \frac{dw}{dt}$

Integrating 2 times, we have:

$w = 1.33t\\angle =0.665t^{2}$

For the first 27.9 s, we have:

w = 37.107 rad/s

angle = 517.6426 rad

For the next seconds, according to the text, the angular velocity is constant so

w = 37.107 rad/s and hence, integrating:

$angle =37.107t$

Then, the time remaining is:

53.5 - 27.9 = 25.6

So for the next 25.6 seconds we have:

$angle = 37.107*25.6=949.9392 rad$

Finally, we add the 2 angles and we have as a result:

$angle = 517.6426+949.9392=1467.5818$

3 0

3 years ago

Calculate the acceleration of a bus whose speed changes from 7 m/s to 16 m/s over a period of 5 s.

Bezzdna [24]

Let’s do this together!

Okay so the acceleration formula is vf-vi over time .

So the initial velocity (vi) 7m/s final velocity (vf) is 16m/s so we’re going to subtract 16-7 which is 9
M/s

So the time is 5s so 9m/s divided into 5s is 1.8m/s/2

So the answer is 1.8m\s2

7 0

3 years ago

A sound wave travels in a straight line at a constant speed of 660 mph. What is

Fed [463]

Answer:

a = 0

Explanation:

The velocity of a sound wave in a straight line is 660 mph. The wave is moving with a constant velocity. It means that the change in velocity is equal to 0.

We know that acceleration of an object is equal to the change in velocity divided by time taken. But here the change in velocity is 0. As a result the acceleration of the sound wave is 0.

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3 years ago