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valentinak56 [21]
4 years ago
13

Classify each of these soluble solutes as a strong electrolyte, a weak electrolyte, or a nonelectrolyte. drag each item to the a

ppropriate bin.
Physics
2 answers:
horrorfan [7]4 years ago
4 0
Three of these are strong electrolytes: 
- HCl (Hydrochloric acid) 
- HNO3 (Nitric acid) 
- NaOH (Sodium hydroxide) 

Two of these are Weak electrolytes: 
- HF (Hydrogen fluoride) 
- HC2H3O2 (Acetic acid) 

And the other two are Non-electrolytes: 
- C6H12O6 (Glucose) 
- C2H5OH (Ethanol) 
Blababa [14]4 years ago
3 0
  • Strong electrolytes: HCl, NaOH, HNO₃
  • Weak electrolytes: HF, HC₂H₃O₂
  • Nonelectrolytes: C₂H₅OH, C₆H₁₂O₆
<h3>Further explanation </h3>
  • Electrolyte solutions are substances that produce ions when dissolved in water and can conduct electricity.
  • A strong electrolyte is a solution that has the strongest electrical conductivity because the solute is completely ionized when dissolved in water.
  • A weak electrolyte is a solution with low electrical conductivity and partially ionized.
  • Nonelectrolytes are solutions that cannot conduct electric current because the solute cannot produce ions.

One of the most significant properties of water is its ability to dissolve a wide variety of substances. Solutions in which water is properly the dissolving medium are called aqueous solutions. For electrolytes, water comes by the most primary solvent.  

  • HCl = hydrochloric acid, a strong acid.
  • HNO₃ = nitric acid, a strong acid .
  • NaOH = sodium hydroxide, a strong base .
  • HF = hydrofluoric acid, a weak acid .
  • HC₂H₃O₂ or CH₃COOH = acetic acid, a weak acid .
  • C₂H₅OH = ethanol, a nonelectrolyte .
  • C₆H₁₂O₆ = glucose, a nonelectrolyte .

<u>Notes: </u>

  • Some acids ionize completely in water, some partially. Thus acids are not all of equal strength in terms of the production of H⁺ ions in solution. If an acid ionizes completely, it is strong acid. If we pass hydrogen chloride gas through water, almost all the molecules ionize to give H⁺ and Cl⁻ ions. Hence, HCl is a strong acid.  
  • If an acid ionizes partially, on the other hand, it is a weak acid. In the ionization of weak acids, some of the ions recombine and remain as molecules. HF is a weak acid. If we pass hydrogen fluoride gas through water, some of it will ionize to give H⁺ and F⁻. Most of the dissolved hydrogen fluoride will remain as HF molecules in water.
  • Bases that completely ionize in water are called strong bases. The bases of alkali metals and some alkaline earth metals are strong, e.g., NaOH, KOH, and Ba(OH)₂. They conduct electricity well in an aqueous solution.
  • Bases that dissociate in water slightly are weak bases, e.g., Mg(OH)₂ and NH₃. Water solutions of weak bases are poor conductors of electricity.
<h3>Learn more </h3>
  1. About the solution as a homogeneous mixture  brainly.com/question/637791
  2. Calculating the pH value of weak base brainly.com/question/9040743
  3. Flammability as one of the chemical properties brainly.com/question/1767022

Keywords: classify, each of these soluble solutes, as a strong electrolyte, a weak, a nonelectrolyte. drag each item to the appropriate bin, acids, bases, dissolve, ionize, conduct electricity, water

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alukav5142 [94]
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Zeroeth Law of Thermodynamics: Two systems in thermal equilibrium with a third system are in thermal equilibrium to each other.

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3 0
3 years ago
If a negatively charged particle enters a region of uniform magnetic field which is perpendicular to the particle's velocity, wi
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Answer:

Same

Explanation:

While moving through a magnetic field in a direction perpendicular to a B-field, a continuous force experienced by a charged particle. If this magnetic field remains uniform, the force exerted also remains same and hence the velocity with which the particle is moving remains same. However, the particle is forced to move on a curved path until it forms a complete circle.

Hence, the kinetic energy remains the same because the speed is same

3 0
3 years ago
A 0.5 kg block of aluminum (caluminum=900J/kg⋅∘C) is heated to 200∘C. The block is then quickly placed in an insulated tub of co
Genrish500 [490]

Answer: When 1.0kg of aluminium block is used, the final temperature of the mixture will be T = 36.2∘C

If 1.0kg copper block is used, T of the mixture will be = 17.4∘C

If 100g (0.1kg) of ice at 0∘C is used, T will be = 64.9∘C

If 25g (0.025Kg) of ice is used, T will be= 147.1∘C

Explanation:

H = mcΘ

heat lost by block = heat gained by water

m₁c₁Θ₁ = m₂c₂Θ₂ where m₁ is mass of aluminium, m₂ is mass of water, c₁ is cAluminium, c₂ is cWater, Θ₁ is temperature change for aluminium, Θ₂ is temperature change for water.

0.5*900*(200-20) = m₁*4186*(20-0)

m₁ = 450*180/83270

<em>m₁ = 0.973kg</em>

<em>when 1.0kg of aluminium block is used, the final temperature of the mixture will be </em><em>T</em>

heat lost by block = heat gained by water

1.0*900*(200-T) = 0.973*4186*(T-0)

180000 - 900T = 4073T

4973T = 180000

T = 180000/4973 = 36.2∘C

<em>If 1.0kg copper block is used, T of the mixture will be</em>

heat lost by block = heat gained by water

1.0*387*(200-T) = 0.973*4186*(T-0)

77400 - 387T = 4073T

4460T = 77400

T = 77400/4460 = 17.4∘C

<em>If 100g (0.1kg) of ice at 0∘C is used, T will be</em>

<em>heat lost by block = heat gained by water + heat used in melting ice to form water at 0∘C</em>

heat used in melting 0.1kg of ice, H = ml, where l= 33600J/Kg

0.5*900*(200-T) = 0.1*4186*(T-0) + 0.1*33600J/Kg

90000 - 450T =  418.6T + 33600

418.6T + 450T = 90000 - 33600

868.6T = 56400

T = 56400/868.6 = 64.9∘C

If 25g (0.025Kg) of ice is used, T will be

0.5*900*(200-T) = 0.025*4186*(T-0) + 0.025*33600J/Kg

90000 - 450T =  104.65T + 8400

104.65T + 450T = 90000 - 8400

554.65T = 81600

T = 81600/554.65 = 147.1∘C

7 0
3 years ago
As a laudably skeptical physics student, you want to test Coulomb's law. For this purpose, you set up a measurement in which a p
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Answer:

force F = 1.66 × 10^{-13} N

Explanation:

given data

proton and an electron = 865 nm

solution

we get here force that is express as

force F = k q1 q2 ÷ r²      ......................1

put here value and we get

force F = 9 × 10^{9} × \frac{1.6\times (10^{-19})^{2}}{865 \times (10^{-9})^{2}}    

force F = 1.66 × 10^{-13} N

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