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3 years ago

If you measured the pH of stomach acid and of bleach,

2 answers:

7 0

The pH of stomach acid would be below 7 (making it an alkaline on the pH scale), but the pH of bleach would be above 7 (making it an acid on the pH scale) Good luck! c:

a_sh-v [17]3 years ago

6 0

It should be B. the pH of stomach acid would be below 7, but the pH of bleach would be above 7.

Because stomach acid is below 7 for sure im pretty sure its around 4. Bleach is extremely high in pH.

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What is the percent composition of C4H10? (4 points)

Marina CMI [18]

Answer:82.7% C and 17.3% H

Explanation:

C4 = 12.0107g/mol x 4 = 48.0428 g/mol

H10 = 1.00794 g/mol x 10 = 10.0794 g/mol

Molar Mass of Butane, C4H10 = 48.0428 g/mol + 10.0794 g/mol= 58.1222 g/mol

percent composition of Carbon is = ( mass of carbon contained in butane / molar mass of Butane) x 100

=(48.0428 /58.1222) x 100% = 0.8265 x 100

=82.65% =82.7% of Carbon.

Percent composition of Hydrogen = (mass of Hydrogen contained in Butane / molar mass of Butane )x 100

( 10.0794/58.122 ) x 100% =0.1734 x 100

= 17.3% OF Hydrogen.

6 0

3 years ago

What changes in our sleep habits as we mature and why?

Yanka [14]

Well, while we change in age, out sleep habits change too.

For instance, when we used to be in our teen age, we used to wake up late. Or, Now that were adults around our 20's we tend to wake up very early. Age tends to change out sleep of ways. Its always good to get at least 7 hours of sleep.

Hoped I answered you question. :)

6 0

3 years ago

A cylinder contains 3.1 L of oxygen at 300 K and 2.7 atm. The gas is heated, causing a piston in the cylinder to move outward. T

zubka84 [21]

Answer: The moles of gas present in the cylinder is 0.34 moles.

Explanation:

Given: $P_{1}$ = 2.7 atm, $V_{1}$ = 3.1 L, $T_{1}$ = 300 K

$P_{2}$ = ?, $V_{2}$ = 9.4 L, $T_{2}$ = 610 K

Formula used to calculate the final temperature is as follows.

$\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}$

Substitute the values into above formula as follows.

$\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{2.7 atm \times 3.1 L}{300 K} = \frac{P_{2} \times 9.4 L}{610 K}\\P_{2} = \frac{5105.7}{2820} atm\\= 1.81 atm$

Now, moles present upon heating the cylinder are as follows.

$P_{2}V_{2} = n_{2}RT_{2}\\1.81 atm \times 9.4 L = n_{2} \times 0.0821 L atm/mol K \times 610 K\\n_{2} = \frac{17.014}{50.081} mol\\= 0.34 mol$

Thus, we can conclude that moles of gas present in the cylinder is 0.34 moles.

6 0

3 years ago

H202-h20-o2 In this process oxygen gas is a

Advocard [28]

Answer:

Oxgeyn gas liquid.

Explanation:

6 0

4 years ago

Draw a schematic of the hydrogen atom with the single proton in the nucleus, and the n=1, n=2, n=3, and n=4 energy level options

max2010maxim [7]

Explanation:

According to Bohr's postulates, the electron in the present in the lower energy level can absorb energy and exits to higher energy level. Also, when this electron returns back to its orbit, it emits some energy.

Since the hydrogen consists of 1 electron and 1 proton. The lowest energy configuration of the hydrogen is when n =1 or, when the electron is present in the K-shell or the ground state.

The possible transition for the electron given in the question is :

n = 2, 3 and 4

The schematic diagram of the hydrogen atom consisting of these four quantum levels in which the electron can jump (Absorption) and comeback to from these energy levels (emission) .

3 0

4 years ago