All categories

3 years ago

Which is a product in the following chemical reaction? CH4 + 2O2 → CO2 + 2H2O

Chemistry

2 answers:

miss Akunina [59]3 years ago

8 0

<span>The products are water (H2O) and carbon dioxide (CO2)</span>

NeTakaya3 years ago

6 0

The correct answer is H20.

In a chemical reaction, there are always two sides, the reactant side and the product side. The reactants are the elements that are reacting together. They are always written at the left side of a chemical equation, with a plus sign written in between two elements. The products are the new compounds that are formed from the reaction of reactants. They are always written at the right side of a chemical equation and a plus sign is used to join them if they are more than one. An arrow pointing to the products usually connect the two side of the equation. For the question give above, the reactant are CH4 and O2 and the products are CO2 and H2O.

You might be interested in

Helllllp me please <br> Part D ends with neon Express your answer as an integer. 20

marysya [2.9K]

Answer:

attach file please

3 0

3 years ago

When water is electrolyzed, it splits into hydrogen and oxygen.

Westkost [7]

The mass of water is equal to the combined mass of hydrogen and oxygen.

This is defined as the quantity of matter in a physical body. The electrolysis reaction of water can be seen below:

2 H₂O ---> 2 H₂ + O₂

We can deduce that 36 grams of H₂O dissociated to give 4 grams of H₂ and 32 grams of O₂ which option D was chosen as the appropriate choice.

Read more about Mass here brainly.com/question/25121535

4 0

3 years ago

How many moles of oxygen are in 5.6 moles of al(oh)3?

Mashcka [7]

5.6 Al(OH)3
5.6 Al, 16.8 O, 16.8 H

16.8 mols of oxegyn in 5.6 mols of Al(OH)3

7 0

3 years ago

A solution of starch at room temperature does not readily decompose to form a solution of simple sugars because

Basile [38]

Explanation:

The starch requires a temperature higher than the room temperature (arround 60 °C) to decompose to form simple sugars. This is because the energy required to break the chemical bonds. Also, it may need the action of some specific enzymes (alpha and beta amilase) to break those bonds.

6 0

3 years ago

Determine the molar mass of a 0.458-gram sample of gas having a volume of 1.20 l at 287 k and 0.980 atm. group of answer choices

lilavasa [31]

Considering the ideal gas law and the definition of molar mass, the molar mass of the sample of gas is 9.17 $\frac{g}{mol}$ .

<h3>Ideal gas law</h3>

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:

P×V = n×R×T

where:

P is the gas pressure.
V is the volume that occupies.
T is its temperature.
R is the ideal gas constant. The universal constant of ideal gases R has the same value for all gaseous substances.
n is the number of moles of the gas.

<h3>Definition of molar mass</h3>

The molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.

<h3>Molar mass of the sample of gas</h3>

In this case you know:

P= 0.980 arm
V= 1.20 L
T= 287 K
R= 0.082 $\frac{atmL}{molK}$
n= ?

Replacing in the ideal gas law:

0.980 atm× 1.20 L= n× 0.082 $\frac{atmL}{molK}$ × 287 K

Solving:

(0.980 atm× 1.20 L)÷ (0.082 $\frac{atmL}{molK}$ × 287 K)= n

<u><em>0.04997 moles= n</em></u>

On the other hand, you know that the<u><em> mass of the sample of gas</em></u> is <u><em>0.458 grams</em></u>. Replacing in the definition of molar mass:

$molar mass=\frac{0.458 grams}{0.04997 moles}$