Answer:
The answer to your question is None, sulfur share of its electrons
Explanation:
Just remember:
Sulfur, S, has 6 electrons in its outermost shell
Hydrogen, H, has 1 electron in its outermost shell
Oxygen, O, has 6 electrons in its outermost shell
See the picture below
The electrons of sulfur are in blue
The electrons of oxygen are in red
The electron in hydrogen is in yellow
Sulfur is the central atom and it shares all its electrons with the oxygen.
Answer: iodine 131 iodine 132 isotopes
Explanation:
Answer:
RNA
Explanation:
The nucleic isolated was quantified by 2 types of fluorescent dyes, which binds only to specific type of nucleic acid. You can find the information on the specificity of dyes on your labsheet or dye supplier's website. For our dyes, however:
- SyBr Green II only emits fluorescent light when it binds to RNA or Single Strand DNA
- PicoGreen only fluoresce when bound to Double Strand DNA
With these information, we know that our nucleic acid is either single strand DNA or RNA, however, it is also mentioned that
"Nucleic acid was isolated by lysing cells in detergent, guanidine isothiocyanate, and DNAse"
DNAse, which is an enzyme that breaks down DNA, destroys any extracted DNA during the process, thus, the only possible nucleic acid we have isolated is RNA
To solve for moles use molar and volume:
M = mol/L
0.02700 m= mol/(.75 L)
mol = .036 mol of Hg(NO3)2
The proportion of Hg(NO3)2 to the Mercury that is used to create
HgS is 1:1 so solve for the moles of Mercury used. So:
.036 * (1 Hg(NO3)2 / 1 Hg) = .036 moles of Hg used to make
HgS
The proportion of Mercury to HgS is 1:1, as an alternative
of doing the obvious math you can conclude that .036 moles of HgS will be
produced because you're given .036 moles of Hg and an excess of S. Use the
molar mass of HgS to determine how many grams will be produced.
.036 moles * 232.66 g/mol = 8.37576 grams of Vermilion is
produced.
The answer is 341.7 g.
(1) Calculate the molar mass (M) of CaCl2 which is the sum of atomic masses (A) of elements:
M(CaCl2) = A(Ca) + 2A(Cl)
A(Ca) = 40.1 g/mol
A(Cl) = 35.45 g/mol
M(CaCl2) = 40.1 + 2 * 35.45 = 40.1 + 70.9 = 111 g/mol
(2) Calculate in how many moles are 535 g:
M(CaCl2) = 111 g/mol
111g : 1mol = 535 g : xmol
x = 535 g * 1mol : 111g = 4.82 mol
(3) Calculate how many grams of Cl are in 4.82 mol:
A(Cl) = 35.45 g/mol
2A(Cl) = 2 * 35.45 = 70.9 g/mol
70.9 g : 1 mol = x : 4.82 mol
x = 70.9 g * 4.82 mol : 1 mol = 341.7 g
