Answer:
o Surface Type- Because the atmosphere is heated by the Earth's surface, the surface type plays an important role in the surface air temperature. o Elevation and Aspect- Higher altitude generally has colder temps b/c the air is less dense and there are fewer molecules to absorb incoming solar radiation.
The Earth's surface is actually what heats the air above it.
Explanation:
The energy from the sun is "short-wave", and as such air is transparent to it. The sunlight goes right through the air without heating it at all. This "short-wave" radiation is absorbed by the Earth which then heats up. The heated Earth then emits it's own radiation but it is in the infrared part of the spectrum or "long-wave" radiation. This heat is what warms the atmosphere.
Answer: 2 grams
Explanation:
chemical formula of C6H:
C6H
relative atomic mass of
C:12
H:1
C6:72
H1:12
relative formula mass of
C6H1=73
molar mass of glucose:
73g
the molar mass is the mass of one mole of a substance.
in
26.2g
of C6H there are
26.2 divide by 73g moles present.
there are 0.358 or 35.8*10-1
I gram of NH3 is 17.03052
2 grams of NH3 is 35
Answer:
c. 2.16 × 10^8 kJ
Explanation:
In the given question, 2 C-12 nuclei were used for the reaction and the mass of C-12 is 12.0000 amu. Therefore, for 2 C-12 nuclei, the mass is 2*12.0000 = 24.0000 amu.
In addition, a Na-23 and a H-1 were formed in the process. The combined mass of the products is 22.989767+1.007825 = 23.997592 amu
The mass of the reactant is different from the mass of the products. The difference = 24.0000 amu - 23.997592 amu = 0.002408 amu.
Theoretically, 1 amu = 1.66054*10^-27 kg
Thus, 0.002408 amu = 0.002408*1.66054*10^-27 kg = 3.99858*10^-30 kg
This mass difference is converted to energy and its value can be calculated using:
E = mc^2 = 3.99858*10^-30 *(299792458)^2 = 3.59374*10^-13 J
Furthermore, 1 mole of hydrogen nuclei contains 6.022*10^23 particles. Thus, we have:
E = 3.59374*10^-13 * 6.022*10^23 = 2.164*10^11 J = 2.164*10^8 kJ
Dissociation of NaCl in water is given as below,
NaCl ₍s₎ → Na⁺ ₍aq₎ + Cl⁻ ₍aq₎
According to this balanced equation the moles on RHS and LHS are as,
Moles on LHS,
NaCl ₍s₎ = 1 Mole
Moles on RHS,
Na⁺ ₍aq₎ = 1 Mole
Cl⁻ ₍aq₎ = 1 Mole
Result:
<span>When one mole of sodium chloride dissociates in water, it produces 2 Moles of Ions.</span>
